Class 10 · Science · Chapter 8

Heredity

How traits pass from parents to offspring and why children still differ from them: variation building up over generations, Mendel's pea experiments (the 3:1 and 9:3:3:1 ratios), how a gene actually controls a trait, how germ cells carry a single set of chromosomes, and how the sex of a human child is decided. A short chapter, but the crosses and the sex-determination flow chart appear in the board paper almost every year.

8 sections12 NCERT questions27 board questions18-question quiz
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Before you startWhat the board asks from this chapter

Class 10 Science is one 80-mark theory paper. Heredity sits in Unit II, World of Living (Chapters 5 to 8), which carries 25 marks in total. On its own the chapter typically fetches 3 to 5 marks: a 1-mark MCQ or assertion-reason on a cross or on sex chromosomes, and then either a 3-mark cross question or a 5-mark question on Mendel's experiments or sex determination. In some years it also turns up as a case-based question built around a Punnett square.

Question typeMarksUsually asked
MCQ1Percentage of tall plants in F1 and F2, the F2 ratio of a dihybrid cross, genotype of a parent from the progeny (the NCERT TtWW question), chromosome number in a human gamete, which parent decides the sex of the child, which of two traits in an asexual population arose earlier.
Assertion–Reason1Tt plants being tall, the recessive trait reappearing in F2, a zygote with XX developing into a girl, acquired traits not being inherited, the father's sperm deciding sex.
Very short answer2What Mendel observed in F1 and F2; how many short plants from a TT × Tt cross; inherited versus acquired traits with an example; how sex is determined in humans; why traits in 60% of a population arose before traits in 10%.
Short answer3Work a monohybrid or dihybrid cross up to F2 with ratios; justify the 50:50 chance of a boy or girl with a flow chart; explain how a gene controls a trait through an enzyme; how germ cells end up with one set of genes; sex determination in different species.
Long answer5How Mendel's experiments show that traits are dominant or recessive and that two traits are inherited independently (with both crosses drawn); dominant and recessive traits plus why a trait can be inherited yet not expressed; sex determination in various species and the human flow chart.
Case-based4A passage describing a pea cross or a family pedigree, or human chromosomes, followed by four sub-questions that ask for a ratio, a genotype, a percentage or a one-line reason.

Hot topics, in order

  1. Monohybrid cross (TT × tt): F1 all tall, F2 3:1 phenotype and 1:2:1 genotype
  2. Dihybrid cross (RRYY × rryy): 9:3:3:1 and what it proves about independent inheritance
  3. Dominant and recessive traits; a trait can be inherited without being expressed
  4. Sex determination in humans: 22 pairs + XX or XY, father decides, flow chart
  5. How a gene controls a trait: gene → enzyme → hormone → tallness; why Tt is tall
  6. Germ cells carry one set of chromosomes, so both parents contribute equally
  7. Variation in asexual versus sexual reproduction; which trait arose earlier
  8. Inherited versus acquired traits: why experiences of a lifetime are not passed on

The whole chapter, in orderNotes

01 Introduction: heredity and variation PYQ 2022 · 2015

Chapter 7 ended with an observation that this chapter picks up: reproduction makes copies, but the copies are never perfect. A child looks like its parents, and yet you can tell the child apart from them. Both halves of that sentence matter. The passing of traits from parents to offspring is heredity. The differences between parents and offspring, and between the offspring themselves, are variation. NCERT opens with a simple example: a human population has a huge amount of variation, yet everyone is recognisably human, because the basic body design is inherited reliably.

The chapter asks two questions and answers them in order. First, where does variation come from and how much of it builds up? That is section 8.1. Second, what are the rules by which traits are inherited? That is section 8.2, which is where Mendel, genes, chromosomes and sex determination live.

One distinction runs through every year's paper, so settle it now. An inherited trait is one carried in the genes (in the DNA of the germ cells) and passed to the next generation: eye colour, blood group, attached or free earlobes. An acquired trait is one an individual picks up during its own lifetime by use, practice or environment: a wrestler's muscles, a scar, a language you learnt. Acquired traits change the body but not the DNA of the germ cells, so they are not inherited. The examiner phrases this as 'we cannot pass on to our progeny the experiences and qualifications earned during our lifetime', and wants exactly that reason. One honest note: this distinction sat in the evolution part of the older textbook, which the rationalised syllabus removed, so the current NCERT chapter doesn't spell it out. The board asked it repeatedly up to 2020 and question banks still carry it, and it is a one-line reason, so keep it.

Exam tip When a question says 'justify', give the reason, not just the fact. 'Acquired traits are not inherited because they do not alter the DNA of the germ cells' earns the mark; 'acquired traits are not inherited' alone does not.

02 8.1 Accumulation of Variation During Reproduction PYQ 2022 · 2018 · 2016

Reproduction hands the offspring a copy of the parent's DNA. Even in asexual reproduction that copying isn't exact, so a bacterium dividing produces two cells that are very similar but not identical. Let each of those divide again and you get four, each carrying its parent's small differences plus one or two new ones of its own. NCERT draws this as a branching tree over three generations: the further you go down, the more the individuals differ, because variation from earlier generations is inherited and new variation is added on top. That is what 'accumulation' means in the section title.

Two kinds of reproduction give two amounts of variation. Asexual reproduction produces only minor differences, the ones that arise from small inaccuracies in DNA copying. Sexual reproduction produces far more, because two parents contribute and their genes are shuffled together in the offspring (Chapter 7 covered the mechanics). This is why NCERT calls sexually reproducing populations much more variable.

Now the exam angle. Is variation good for the individual? Not necessarily. NCERT's example is a population of bacteria in temperate water. If a heat wave hits, most die, but the few that happen to carry a heat-resistant variation survive and multiply. The variation was useless to the others, and it was useless to the resistant ones too until the environment changed. So the answer to 'how does variation help?' is: it gives the species a better chance of surviving a change in its surroundings. Nature selects which variants persist; the individual doesn't choose.

The in-text question everyone gets asked: in an asexually reproducing population, trait A is in 10% of individuals and trait B in 60%. Which arose earlier? B, because in asexual reproduction variation is passed on faithfully, so a trait that has had more generations to spread is present in a larger fraction of the population.

Fraction of population showing a trait ∝ number of generations since the trait arose (asexual reproduction)
larger fractiontrait arose earliersmaller fractiontrait arose more recently
Exam tip The heat-wave bacteria example is the one NCERT uses; quote it. Do not say variation 'helps the individual survive'. Say it improves the survival chances of the species when the environment changes.

03 8.2 Heredity and 8.2.1 Inherited Traits PYQ 2020 · 2019

Heredity is the reliable transmission of traits from one generation to the next. NCERT makes a point that is easy to miss: the very fact that a trait is inherited reliably, generation after generation, tells you that a rule is operating. If inheritance were random, you couldn't have said 'children look like their parents'. Section 8.2 is about finding those rules.

The first example is human earlobes. Look at the lower part of the ear: in some people the lobe hangs free below the point where it joins the head, in others it is attached along its whole length. Free and attached earlobes are two forms of one trait, and which form you have runs in families. NCERT suggests a small survey: note the earlobe type of students and of their parents and see whether children with attached lobes tend to have parents with attached lobes. The board has turned exactly this into a 1-mark question (two parents with attached earlobes, a recessive trait: what is the chance of a child with attached earlobes? 100%, because both parents can pass on only the recessive form).

What you should take from 8.2.1 is the shape of the reasoning, not the earlobes. To decide how a trait is inherited, you look at parents and children together, over more than one generation, and you count. That is what Mendel did with pea plants, with one advantage: he could set up the crosses himself, choose pure-breeding parents, and grow hundreds of offspring. Humans don't give you that control, which is why the chapter moves to peas in the next section, and why the NCERT exercise on light-coloured eyes says you cannot decide dominance from the observation that children with light eyes tend to have light-eyed parents.

Exam tip Free and attached earlobes is NCERT's example of an inherited human trait. Give it when asked for one; it is safer than eye colour, which the exercise itself says you cannot classify from casual observation.

04 8.2.2 Rules for the Inheritance of Traits – Mendel's Contributions (the monohybrid cross) PYQ 2023 · 2022 · 2019 · 2018 · 2017

Gregor Johann Mendel (1822–1884) worked with the garden pea and chose characters that come in two clear-cut forms: round or wrinkled seeds, yellow or green seeds, tall or short plants, violet or white flowers. He took pure-breeding parents (tall plants that always gave tall offspring, short plants that always gave short) and crossed them. The generation from this cross is called F1 (first filial). He then let the F1 plants self-pollinate to get F2.

Here is what he saw, and every marking scheme wants these three observations in order. First, all F1 plants were tall. Not medium height, not a blend: tall. Second, when F1 plants were selfed, F2 had both tall and short plants, in the ratio of about three tall to one short. Third, the short plants that reappeared were as short as the original short parent. So the trait for shortness had not been lost in F1; it had been carried along without being expressed.

The explanation. Each plant carries two copies of the factor (we now say gene) for height. Write the tall version as T and the short version as t. The pure tall parent is TT, the pure short parent is tt. Each gamete carries only one copy, so the F1 plant gets T from one parent and t from the other and is Tt. It is tall because T is dominant: one copy is enough to show the trait. The t version is recessive: it shows only when both copies are t. When Tt is selfed, gametes T and t combine at random and give TT, Tt, tT and tt in equal numbers. That is the genotype ratio 1 TT : 2 Tt : 1 tt. Since TT and Tt both look tall, the phenotype ratio is 3 tall : 1 short.

Two things follow that the board loves to ask. A trait can be inherited but not expressed (t in the F1 plant). And you cannot tell TT from Tt by looking; you have to cross and count. A cross of Tt with tt gives 1 tall : 1 short, and a cross of TT with anything gives all tall, which is how the 2018 question about two tall parents producing no short offspring is settled.

P: TT (tall) × tt (short) → F1: all Tt (tall)
Tdominant factor for tallnesstrecessive factor for shortness
F1 selfed: Tt × Tt → F2: 1 TT : 2 Tt : 1 tt (genotype), 3 tall : 1 short (phenotype)
1:2:1genotypic ratio3:1phenotypic ratio
Tt × tt → 1 Tt (tall) : 1 tt (short)
1:1the cross that reveals whether a tall plant is TT or Tt
Exam tip Always draw the cross as a chart: P, gametes, F1, then a four-box Punnett square for F2. Write both ratios and label which is genotype and which is phenotype. Half the marks sit in the labelled chart.

05 8.2.2 continued: two traits together (the dihybrid cross) PYQ 2024 · 2017

Mendel then asked whether two traits travel together or separately. He crossed pea plants that were tall with round seeds and plants that were short with wrinkled seeds. F1 were all tall with round seeds, so tall and round are the dominant forms. If the two traits were tied together, F2 should contain only the two parental types: tall-round and short-wrinkled. Instead F2 contained tall-round, tall-wrinkled, short-round and short-wrinkled plants. Some tall plants had wrinkled seeds and some short plants had round seeds. New combinations appeared, so the two traits are inherited independently of each other.

The figure in NCERT uses seed shape and seed colour, and that is the version the 2024 paper asked. Parents RRYY (round, yellow) and rryy (wrinkled, green). Each parent gives one gamete type, RY or ry, so F1 is RrYy: round and yellow, because R and Y are dominant. An F1 plant makes four kinds of gamete in equal numbers, RY, Ry, rY and ry, because the R/r pair and the Y/y pair separate independently. A 4 × 4 Punnett square gives 16 combinations, and counting phenotypes gives 9 round-yellow : 3 round-green : 3 wrinkled-yellow : 1 wrinkled-green. The 9:3:3:1 ratio is the fingerprint of a dihybrid cross; the 9 and the 1 are the parental types, the two 3s are the new combinations.

Check the ratio by looking at one trait at a time. Round : wrinkled in F2 is (9 + 3) : (3 + 1) = 12 : 4 = 3 : 1. Yellow : green is (9 + 3) : (3 + 1) = 3 : 1 as well. Each trait still follows the monohybrid rule; the dihybrid ratio is just the two 3:1 ratios multiplied together, and that multiplication is only possible if the traits are independent. That is the sentence to end a 3-mark answer with.

Fractions worth having ready: 9/16 show both dominant traits, 1/16 show both recessive traits, and only 1 in 16 is RRYY, the pure double dominant. If a question changes the parents (say RRYy × RRYy), don't reach for 9:3:3:1; work the square. Here every plant is RR, and Yy × Yy gives 3 yellow : 1 green, so 75% round-yellow and 25% round-green.

P: RRYY (round, yellow) × rryy (wrinkled, green) → F1: RrYy (all round, yellow)
R, rround (dominant), wrinkled (recessive)Y, yyellow (dominant), green (recessive)
F1 selfed: RrYy × RrYy → F2: 9 round-yellow : 3 round-green : 3 wrinkled-yellow : 1 wrinkled-green
gametes of RrYyRY, Ry, rY, ry in equal numbers16boxes in the Punnett square
Each trait separately in F2: 12 round : 4 wrinkled = 3 : 1; 12 yellow : 4 green = 3 : 1
3:1the monohybrid ratio hidden inside 9:3:3:1
Exam tip The 9:3:3:1 ratio is a phenotype ratio for F2. F1 of a dihybrid cross is not a ratio at all: it is all one type. Students lose a mark by writing 9:3:3:1 against F1.

06 8.2.3 How do these Traits get Expressed? PYQ 2022 · 2020

The next question is what a gene actually does to make a plant tall or short. Cellular DNA carries the information for making proteins, and a gene is the section of DNA that provides the information for one protein. Take height. A plant grows tall because a growth hormone is made in enough quantity, and how much hormone is made depends on how efficiently an enzyme works to produce it. The gene for this enzyme is what we have been calling the height gene. If the gene is in its normal form, the enzyme is efficient, a lot of hormone is made and the plant is tall. If the gene is altered, the enzyme is less efficient, the hormone is scarce and the plant is short. So a gene controls a trait by controlling a protein.

This is also the real reason Tt plants are tall. A Tt plant has one efficient copy of the enzyme gene and one poor copy. The efficient copy alone makes enough hormone, so the plant reaches full height. Only a tt plant, with two poor copies, falls short. Dominance, then, isn't a magic property of the letter T; it is a consequence of one working copy being sufficient. A 2022 assertion-reason item was built on precisely this chain: height controlled by enzyme efficiency, and the enzyme controlled by the gene.

Notice the logic the section is setting up. Mendel's results need each plant to carry two copies of each gene. If both parents are to contribute one copy each, then a germ cell must carry only one copy of every gene, not two. How that single set is produced is the subject of the next part of 8.2.3, and it brings in chromosomes.

Gene (DNA) → protein (enzyme) → amount of plant hormone → height of plant
efficient enzymemore hormone, tall plantaltered gene, poor enzymeless hormone, short plant
Exam tip If asked 'how do genes control characteristics', give the full chain in one line: gene, enzyme, hormone, trait. Naming the hormone as 'a plant growth hormone' is enough; NCERT does not name it.

07 8.2.3 continued: genes, chromosomes and the single set in germ cells PYQ 2019 · 2017

Genes sit on chromosomes. In a body cell each chromosome is present as a pair, so each gene is present in two copies, one on each member of the pair. The pea plant's Tt is one such pair: T on one chromosome, t on its partner. When germ cells are made, the two members of every pair separate and a gamete receives just one chromosome from each pair. So a gamete carries one complete set of chromosomes, and therefore one copy of every gene. Which member of a pair a gamete receives is a matter of chance, and it may be the copy that came from the plant's mother or the copy that came from its father. That randomness is what makes an Rr Yy plant produce RY, Ry, rY and ry gametes in equal numbers, and it is the physical basis of independent inheritance.

At fertilisation, a male gamete with one set meets a female gamete with one set, and the zygote has the normal two sets again. This is the answer to the NCERT exercise question on how the equal genetic contribution of both parents is ensured: every cell has two copies of each chromosome; germ cells carry only one; the offspring gets one full set from the egg and one from the sperm, so the mother and father contribute equally, one copy of every gene each.

NCERT adds a caution that examiners like. The mechanism described here works for organisms with two copies of each chromosome, but not all organisms are like that. Some do not reproduce sexually at all, and some have unusual arrangements. Keep the claim to what the chapter says: in organisms such as peas and humans, each germ cell gets one chromosome from every pair, so each parent contributes one set.

A quick numerical anchor for humans, which the next section needs: body cells have 46 chromosomes as 23 pairs, so a gamete carries 23 chromosomes, and a zygote has 23 + 23 = 46.

Body cell: 2 sets of chromosomes → germ cell: 1 set → zygote (egg + sperm): 2 sets
1 setone chromosome from each pair, chosen at random2 setsone from the mother, one from the father
Human: 46 chromosomes (23 pairs) in body cells; 23 in a gamete
23 pairs22 pairs of autosomes + 1 pair of sex chromosomes
Exam tip A germ cell has one copy of each gene, not half a gene and not half the chromosomes chosen at random. Say 'one chromosome from each pair' and you have said it correctly.

08 8.3 Sex Determination: How is the Sex of a Child Determined? PYQ 2022 · 2017 · 2016 · 2013

Species that reproduce sexually have two sexes, and different species decide the sex of a new individual in different ways. NCERT gives three. In some reptiles, the temperature at which the fertilised eggs are kept decides whether the animals developing in them will be male or female. In snails, an individual can change its sex, which shows that sex in these animals is not fixed by genes. In human beings the sex of a child is largely determined genetically, by the chromosomes it inherits.

Here is the human mechanism, and the flow chart the board asks for. Every body cell has 23 pairs of chromosomes. 22 pairs are the same in both sexes and are called autosomes. The 23rd pair is the pair of sex chromosomes. In a woman this pair is two X chromosomes, written XX; in a man it is one X and one much shorter Y, written XY. A woman's egg therefore always carries 22 + X. A man's sperm carries either 22 + X or 22 + Y, in equal numbers, because the X and Y separate when sperm are made. If an X-carrying sperm fertilises the egg, the zygote is XX and the child is a girl. If a Y-carrying sperm fertilises it, the zygote is XY and the child is a boy.

Three conclusions follow, and you should write all three. Every child receives an X from the mother, so the mother does not decide sex. The sex of the child is decided by which chromosome, X or Y, it receives from the father. And since the two kinds of sperm are produced in equal numbers and fertilisation is a matter of chance, the probability of a boy is 50% and of a girl is 50%, which is why roughly half the children born are boys and half girls.

The question that keeps returning: 'the sex of a newborn is a matter of chance and neither parent may be considered responsible for it'. Justify with a flow chart. Draw the parents (44 + XX and 44 + XY), their gametes (22 + X; 22 + X or 22 + Y), the two possible zygotes, and label them girl and boy in a 1:1 ratio. The chart is half the answer; the sentence about the father's sperm and chance is the other half.

Female: 44 + XX; male: 44 + XY
4422 pairs of autosomesXX, XYsex chromosomes
Egg: 22 + X (always); sperm: 22 + X or 22 + Y (50% each)
22 + X sperm + eggXX zygote, girl22 + Y sperm + eggXY zygote, boy
P(boy) = P(girl) = ½
½because the two kinds of sperm are equal in number and fertilisation is random
Exam tip Write the Y chromosome as 'much shorter' than X and the child's sex as decided by the father's sperm. Saying 'the father is responsible' loses the point; the wording is that it is a matter of chance, decided by which sperm happens to fertilise the egg.

VocabularyKey terms

HeredityThe transmission of traits (characters) from parents to their offspring through the genes in the germ cells.
VariationThe differences in traits between parents and offspring, or between individuals of the same species. It arises from small errors in DNA copying and, much more, from the shuffling of genes in sexual reproduction.
Trait (character)A recognisable feature of an organism, such as plant height, seed shape or earlobe type, that can be inherited.
GeneA section of DNA that carries the information for making one protein, and through that protein controls a trait. Mendel called it a factor.
Dominant traitThe form of a trait that is expressed even when only one copy of its gene is present, such as tallness (T) in pea plants. It appears in all of F1.
Recessive traitThe form of a trait that is expressed only when both copies of the gene are of that form, such as shortness (tt). It is hidden in F1 and reappears in a quarter of F2.
GenotypeThe genetic make-up of an organism for a trait, written with letters: TT, Tt or tt. The term is not used in NCERT, but marking schemes use it and expect you to.
PhenotypeThe visible form of the trait, such as tall or short. TT and Tt have the same phenotype (tall) but different genotypes.
Pure (homozygous)An organism with two identical copies of a gene, TT or tt, which breeds true for that trait. Mendel started every cross with pure parents.
Hybrid (heterozygous)An organism with two different copies of a gene, such as Tt. It shows the dominant trait but carries and can pass on the recessive one.
F<sub>1</sub> generationThe first filial generation: the offspring of a cross between the two parents (P). In Mendel's tall × short cross, all of F1 were tall.
F<sub>2</sub> generationThe generation obtained by self-pollinating (or crossing among) the F1 plants. In a monohybrid cross it shows the 3:1 ratio.
Monohybrid crossA cross that follows one pair of contrasting traits, such as tall × short. F2 phenotype ratio 3:1, genotype ratio 1:2:1.
Dihybrid crossA cross that follows two pairs of contrasting traits at once, such as round-yellow × wrinkled-green. F2 phenotype ratio 9:3:3:1, showing the two traits are inherited independently.
ChromosomeA thread-like structure in the nucleus made of DNA, which carries genes. Body cells have chromosomes in pairs; a germ cell has one chromosome from each pair.
AutosomesThe 22 pairs of chromosomes in humans that are the same in males and females and do not decide sex.
Sex chromosomesThe 23rd pair of human chromosomes, XX in a female and XY in a male, which decides the sex of the child. The Y chromosome is much shorter than the X.
Acquired traitA trait developed by an individual during its lifetime through use, injury or environment, such as trained muscles or a scar. It does not change the DNA of germ cells and so is not inherited.

Keep this on one pageFormula sheet

NameExpressionNotes
Monohybrid cross, F<sub>1</sub>TT × tt → all Tt (tall)Pure dominant × pure recessive; every F1 plant shows the dominant trait and carries the recessive one.
Monohybrid cross, F<sub>2</sub>Tt × Tt → 1 TT : 2 Tt : 1 tt; phenotype 3 tall : 1 shortGenotype ratio 1:2:1, phenotype ratio 3:1. 75% tall, 25% short.
Hybrid × pure recessiveTt × tt → 1 Tt : 1 tt (50% tall, 50% short)The cross that shows whether a tall plant is TT or Tt. TT × tt or TT × Tt gives no short plants at all.
Dihybrid crossRRYY × rryy → F1 RrYy; F2 9 : 3 : 3 : 19 round-yellow, 3 round-green, 3 wrinkled-yellow, 1 wrinkled-green out of 16. Each trait alone is still 3:1.
Fractions in a dihybrid F<sub>2</sub>9/16 both dominant; 1/16 both recessive; 1/16 pure double dominant (RRYY)Use these for 'what fraction' or 'what percentage' questions: 9/16 = 56.25%, 1/16 = 6.25%.
Human chromosome count46 = 23 pairs = 22 pairs of autosomes + 1 pair of sex chromosomesBody cells 46; gamete 23 (22 + X in an egg, 22 + X or 22 + Y in a sperm).
Sex chromosomesFemale XX, male XY; Y is much shorter than XThe child always gets X from the mother; X or Y from the father decides the sex.
Probability of a boy or a girlP(boy) = P(girl) = 1/2 = 50%Half the sperm carry X and half carry Y, and fertilisation is random.
How a gene worksGene → enzyme → plant hormone → tallnessAn altered gene gives a less efficient enzyme, less hormone and a short plant. One good copy (Tt) is enough for full height.
Which trait arose earlier (asexual population)Trait in 60% arose before trait in 10%In asexual reproduction variation is passed on faithfully, so an older trait has spread to a larger fraction.

Practise with a pencilDiagrams that earn marks

Monohybrid cross: inheritance of height in pea plants over two generations

Draw three rows. Top row: parents TT (tall) and tt (short) with a cross sign, and below each parent its gametes, T and t. Middle row: F1, a single genotype Tt labelled tall. Bottom: a 2 × 2 Punnett square with gametes T and t along the top and side, filled in as TT, Tt, Tt, tt. Under it write the genotype ratio 1 TT : 2 Tt : 1 tt and the phenotype ratio 3 tall : 1 short. Label P, F1 and F2 clearly; unlabelled generations lose a mark.

Dihybrid cross: independent inheritance of seed shape and seed colour

Parents RRYY (round, yellow) × rryy (wrinkled, green), gametes RY and ry, F1 RrYy labelled round-yellow. Then a 4 × 4 Punnett square with the four gametes RY, Ry, rY, ry along both the top and the side. Fill all 16 boxes, then count and write the phenotype tally: 9 round-yellow, 3 round-green, 3 wrinkled-yellow, 1 wrinkled-green, ratio 9:3:3:1. If time is short in the exam, you may write the count without drawing every box, but the four gametes and the ratio must be there.

Sex determination in human beings (flow chart)

Two boxes at the top: Female parent 44 + XX and Male parent 44 + XY. Arrows down to gametes: one egg type 22 + X from the mother; two sperm types 22 + X and 22 + Y from the father. Cross-arrows to two zygotes: 44 + XX labelled girl, 44 + XY labelled boy. Write 50% : 50% or 1 : 1 under the zygotes and a one-line note that the sperm decides the sex. Show the Y as shorter than the X if you draw the chromosomes.

Creation of diversity over successive generations (asexual reproduction)

Draw one cell at the top. Below it, two daughter cells, each with a tiny mark of difference (a different shade or a small dot). Below those, four cells in the third generation, each inheriting its parent's mark and adding one of its own. Caption: variation from each generation is inherited, and new variation is added, so it accumulates. This is the NCERT figure for section 8.1 and it needs no more than three generations.

TextbookNCERT questions the board keeps asking

Page 143, Q1 If a trait A exists in 10% of a population of an asexually reproducing species and a trait B exists in 60% of the same population, which trait is likely to have arisen earlier?2 m

Trait B. In asexual reproduction there is very little variation, and whatever variation arises is passed on faithfully to the next generation. So a trait that has been present for more generations has had more time to spread and is found in a larger fraction of the population. Trait B is in 60% of the population, trait A in only 10%, so trait B arose earlier and trait A is the more recent one.

Page 143, Q2 How does the creation of variations in a species promote survival?2 m

Variation gives a species a better chance of surviving a change in its environment. Different individuals carry different variations; most of these are neutral or even unhelpful in the present conditions. But if the environment changes, a variation that happened to be useless may become the one that allows survival. NCERT's example: in a population of bacteria living in temperate water, a few carry a variation that makes them heat-resistant. During a heat wave most bacteria die, but the resistant ones survive and multiply. Without that variation the whole population might have been wiped out. So variation does not necessarily help the individual, but it protects the species.

Page 147, Q1 How do Mendel's experiments show that traits may be dominant or recessive?3 m

Mendel crossed pure tall pea plants (TT) with pure short pea plants (tt). All the F1 plants were tall; none were short and none were of intermediate height. When the F1 plants were allowed to self-pollinate, the F2 generation had both tall and short plants in the ratio 3 : 1. The short trait had not disappeared in F1; it was present but not expressed, and reappeared in F2. The trait that is expressed in F1 (tallness) is dominant, and the trait that is hidden in F1 but reappears in F2 (shortness) is recessive. Cross chart: TT × tt → F1 all Tt (tall); Tt × Tt → F2 1 TT : 2 Tt : 1 tt, that is 3 tall : 1 short.

Page 147, Q2 How do Mendel's experiments show that traits are inherited independently?3 m

Mendel crossed plants that differed in two traits at once: tall plants with round seeds and short plants with wrinkled seeds (in the NCERT figure, round-yellow RRYY × wrinkled-green rryy). All F1 plants showed both dominant traits (tall and round; or round and yellow). When F1 plants were selfed, the F2 generation contained not only the two parental combinations but also two new ones: tall plants with wrinkled seeds and short plants with round seeds. The four types appeared in the ratio 9 : 3 : 3 : 1. If the two traits were inherited together, only the parental combinations would have appeared. The appearance of new combinations shows that each trait is inherited independently of the other. Looking at one trait at a time, round : wrinkled is 12 : 4 = 3 : 1 and yellow : green is also 3 : 1, so each trait still follows its own monohybrid rule.

Page 147, Q3 A man with blood group A marries a woman with blood group O and their daughter has blood group O. Is this information enough to tell you which of the traits, blood group A or O, is dominant? Why or why not?3 m

No, the information is not enough. The daughter's blood group O is consistent with either possibility. If A is dominant and O is recessive, the father could be heterozygous (one gene for A, one for O); he would then pass the O gene to the daughter, who gets a second O gene from the mother and has blood group O. If instead O is dominant and A recessive, the father must be pure A (two A genes) and the mother, having group O, carries at least one dominant O gene; the daughter could receive that O gene and show blood group O. Since both explanations fit what we see, we cannot decide which trait is dominant from this single family. We would need to study many families over more than one generation.

Page 147, Q4 How is the sex of the child determined in human beings?3 m

Humans have 23 pairs of chromosomes. 22 pairs are autosomes and are the same in both sexes. The 23rd pair is the pair of sex chromosomes: XX in a woman and XY in a man. The mother's eggs all carry one X chromosome. The father's sperm carry either an X or a Y, in equal numbers. If a sperm with X fertilises the egg, the zygote is XX and develops into a girl; if a sperm with Y fertilises the egg, the zygote is XY and develops into a boy. So every child gets an X from the mother, and the sex of the child is decided by whether it gets an X or a Y from the father. Because the two kinds of sperm are equal in number, the chances of a boy and a girl are equal, 50% each.

8.1 A Mendelian experiment consisted of breeding tall pea plants bearing violet flowers with short pea plants bearing white flowers. The progeny all bore violet flowers, but almost half of them were short. This suggests that the genetic make-up of the tall parent can be depicted as (a) TTWW (b) TTww (c) TtWW (d) TtWw1 m

(c) TtWW. Work each trait separately. All progeny had violet flowers, so the tall parent must have had two dominant genes for violet, WW; if it were Ww, some white-flowered progeny (ww) would have appeared with the white (ww) parent. Half the progeny were short, so the tall parent must be Tt: a Tt × tt cross gives 1 tall : 1 short, whereas TT × tt gives all tall. Putting the two together, the tall parent is TtWW.

8.2 A study found that children with light-coloured eyes are likely to have parents with light-coloured eyes. On this basis, can we say anything about whether the light eye colour trait is dominant or recessive? Why or why not?2 m

No, we cannot. The observation only tells us that eye colour is inherited, not how. To decide whether light eye colour is dominant or recessive, we would need to know the eye colour of both parents and of all their children over at least two generations, and to count the numbers of each type. For example, we would need to know whether two light-eyed parents ever have a dark-eyed child (which would make light colour dominant and the parents hybrids) or whether two dark-eyed parents can have a light-eyed child (which would make light colour recessive). A statement that children with light eyes tend to have light-eyed parents is consistent with both possibilities.

8.3 Outline a project which aims to find the dominant coat colour in dogs.3 m

Follow Mendel's method. (1) Select pure-breeding dogs of two contrasting coat colours, say a pure black male and a pure white female (pure means each has shown only that colour in its family for several generations). (2) Cross them and record the coat colour of every pup in the F1 litter. If all F1 pups are black, black is the dominant colour and white is recessive; if all are white, the reverse. (3) To confirm, cross two F1 dogs with each other. Among the F2 pups the recessive colour should reappear in about one-quarter of them, giving a ratio close to 3 : 1. (4) Repeat with several pairs and pool the counts, because a single litter is too small to show the ratio reliably. The colour that appears in all of F1 and in three-quarters of F2 is the dominant coat colour.

8.4 How is the equal genetic contribution of male and female parents ensured in the progeny?3 m

Every body cell of a sexually reproducing organism has two copies of each chromosome, and therefore two copies of every gene, one from each parent. When germ cells (gametes) are formed, the two chromosomes of each pair separate and each gamete receives only one chromosome from every pair, so it carries a single set of chromosomes and one copy of each gene. The male gamete and the female gamete each carry one such set. At fertilisation the two sets combine, and the zygote once again has two copies of every chromosome, one from the father and one from the mother. In this way each parent contributes exactly one set of genes, so their genetic contribution to the progeny is equal. In humans, for example, the egg carries 23 chromosomes and the sperm carries 23, and the zygote has 46.

Exemplar SA In a monohybrid cross between pure tall and pure short pea plants, what fraction of the tall plants in F2 are pure (true-breeding)? Explain.2 m

One-third. In F2 the genotypes are 1 TT : 2 Tt : 1 tt. The tall plants are TT and Tt, three out of every four plants. Of these three, only the TT plant is pure and will breed true; the two Tt plants are hybrids and will give short offspring when selfed. So among the tall F2 plants, 1 out of 3 is pure tall and 2 out of 3 are hybrid tall. (Of all F2 plants, one-quarter are pure tall.)

Exemplar SA Distinguish between inherited traits and acquired traits with one example of each. Why are acquired traits not inherited?3 m

Inherited traits are those that are carried by the genes in the DNA of the germ cells and are passed from parents to offspring: free or attached earlobes, blood group, eye colour. Acquired traits are those an individual develops during its own lifetime because of its activities or its environment: the muscles of a wrestler, a scar, the ability to speak a language, the low weight of a starving animal. Acquired traits are not inherited because they involve changes in the body's non-reproductive (somatic) cells only. They do not alter the DNA of the germ cells, and only the DNA of germ cells is passed to the next generation. This is why the experiences and qualifications earned during a lifetime cannot be passed on to children.

Previous years and frequently askedBoard questions with model answers

MCQ If a pure tall pea plant is crossed with a pure dwarf pea plant, what percentage of the F1 and F2 generations respectively will be tall?
  1. 25%, 25%
  2. 50%, 50%
  3. 75%, 100%
  4. 100%, 75%
CBSE 20231 m
Answer: (d)
TT × tt gives all Tt, so F1 is 100% tall. Selfing Tt gives 1 TT : 2 Tt : 1 tt, so three-quarters of F2, 75%, are tall.
MCQ Attached earlobes in humans is an inherited, recessive trait. What is the chance that two parents who both have attached earlobes will have a child with attached earlobes?
  1. 25%
  2. 50%
  3. 75%
  4. 100%
CBSE 20201 m
Answer: (d)
A recessive trait shows only when both gene copies are recessive, so each parent is ee and can give only e. Every child is ee, so 100% have attached earlobes.
MCQ In Mendel's dihybrid cross between pea plants with round yellow seeds (RRYY) and plants with wrinkled green seeds (rryy), the phenotypic ratio obtained in the F2 generation is
  1. 3 : 1
  2. 1 : 2 : 1
  3. 9 : 3 : 3 : 1
  4. 1 : 1 : 1 : 1
Frequently asked1 m
Answer: (c)
F1 is RrYy, which makes four gamete types; the 16-box Punnett square gives 9 round-yellow : 3 round-green : 3 wrinkled-yellow : 1 wrinkled-green.
MCQ The number of chromosomes in a human egg cell is
  1. 46, including one pair of sex chromosomes
  2. 23, including one X chromosome
  3. 23, including one X or one Y chromosome
  4. 22, with no sex chromosome
Frequently asked1 m
Answer: (b)
A gamete carries one chromosome from each of the 23 pairs. The egg always carries 22 autosomes plus one X; it is the sperm that carries either X or Y.
MCQ A tall pea plant with genotype Tt is crossed with a short pea plant (tt). The percentage of tall plants among the offspring is
  1. 0%
  2. 25%
  3. 50%
  4. 75%
Frequently asked1 m
Answer: (c)
Tt × tt gives 1 Tt : 1 tt, so half the offspring are tall and half short. (The 75% figure belongs to Tt × Tt, not to this cross.)
MCQ In an asexually reproducing population, trait A is found in 10% of individuals and trait B in 60%. Which statement is correct?
  1. Trait A arose earlier because it is rarer
  2. Trait B arose earlier because it has spread to more individuals
  3. Both arose at the same time
  4. Nothing can be said about which arose earlier
Frequently asked1 m
Answer: (b)
Asexual reproduction passes variation on faithfully, so a trait that has existed for more generations has spread to a larger fraction of the population.
MCQ A pea plant with the genotype Tt is tall because
  1. the two genes blend to give an intermediate height, which is called tall
  2. the gene T is dominant and one copy is enough to produce sufficient growth hormone
  3. the gene t is lost when the plant grows
  4. tallness in peas does not depend on genes
Frequently asked1 m
Answer: (b)
The dominant gene T codes for an efficient enzyme that makes enough plant hormone, so a single copy gives full height. The t gene is still present and can be passed on; it is not lost.
Assertion–Reason Assertion (A): A zygote with two X chromosomes develops into a boy. Reason (R): The sex of a child is decided by the sex chromosome it receives from the father.
  1. Both A and R are true and R is the correct explanation of A
  2. Both A and R are true but R is not the correct explanation of A
  3. A is true but R is false
  4. A is false but R is true
Frequently asked1 m
Answer: (d)
An XX zygote develops into a girl, so A is false. R is true: the mother always gives X, so the father's X or Y decides the sex.
Assertion–Reason Assertion (A): A pea plant with the genotype Tt is as tall as a pea plant with the genotype TT. Reason (R): T is dominant over t, and one copy of T produces enough of the enzyme that makes the growth hormone.
  1. Both A and R are true and R is the correct explanation of A
  2. Both A and R are true but R is not the correct explanation of A
  3. A is true but R is false
  4. A is false but R is true
Frequently asked1 m
Answer: (a)
Both are true and R explains A: one efficient copy of the gene is sufficient for full height, which is exactly what dominance means at the level of the enzyme.
Assertion–Reason Assertion (A): In Mendel's monohybrid cross, short plants reappear in the F2 generation although all F1 plants were tall. Reason (R): The trait for shortness was not lost in F1; it was present but not expressed because it is recessive.
  1. Both A and R are true and R is the correct explanation of A
  2. Both A and R are true but R is not the correct explanation of A
  3. A is true but R is false
  4. A is false but R is true
Frequently asked1 m
Answer: (a)
F1 plants are Tt; the t is carried unexpressed and combines as tt in one-quarter of F2. R is the correct explanation.
Assertion–Reason Assertion (A): The skills and experiences a person gains during life are not passed on to their children. Reason (R): Acquired traits do not bring about any change in the DNA of the germ cells.
  1. Both A and R are true and R is the correct explanation of A
  2. Both A and R are true but R is not the correct explanation of A
  3. A is true but R is false
  4. A is false but R is true
Frequently asked1 m
Answer: (a)
Only the DNA of germ cells is inherited. Acquired traits change body cells, not germ-cell DNA, so they cannot be passed on. R explains A.
Very short answer Mendel took tall pea plants and short pea plants and produced F1 progeny through cross-fertilisation. What did Mendel observe in the F1 progeny? What did he observe when F1 plants were self-pollinated?CBSE 20182 m

(i) All the F1 plants were tall. There were no short plants and no plants of intermediate height, showing that tallness is dominant over shortness. (1 mark)

(ii) On self-pollinating the F1 plants, the F2 generation had both tall and short plants in the ratio 3 : 1. The short trait, hidden in F1, reappeared in F2, showing that it had been inherited but not expressed. (1 mark)

Very short answer Two tall pea plants, one of genotype TT and the other Tt, are crossed to produce 20 offspring. How many of the offspring will be short? Explain with a cross.CBSE 20182 m

None (zero). Gametes of TT: T only. Gametes of Tt: T or t. Offspring: TT and Tt in equal numbers (1 : 1). Both genotypes contain at least one dominant T, so all 20 plants are tall. A short plant needs tt, and the TT parent cannot supply a t. (Cross chart 1 mark, answer with reason 1 mark.)

Very short answer In a cross between pure red-flowered and pure white-flowered plants, all F1 plants had red flowers. When the F1 plants were self-pollinated, 75% of the F2 plants had red flowers and 25% had white flowers. Name the dominant trait and write the genotypes of the parents, the F1 plants and the F2 plants.CBSE 20222 m

Red flower colour is dominant, because it appears in all of F1 and in three-quarters of F2; white is recessive. Genotypes: parents RR (red) and rr (white); F1 all Rr (red); F2 1 RR : 2 Rr : 1 rr, of which RR and Rr are red (75%) and rr is white (25%).

Very short answer How is the sex of a child determined in human beings? Which parent's gamete decides it?Frequently asked2 m

Humans have 22 pairs of autosomes and one pair of sex chromosomes: XX in females, XY in males. The egg always carries an X; a sperm carries either X or Y. An X sperm fertilising the egg gives XX, a girl; a Y sperm gives XY, a boy. So the sex of the child is decided by the father's sperm, by whether it carries X or Y; the mother contributes an X in every case.

Very short answer 'We cannot pass on to our progeny the experiences and qualifications earned during our lifetime.' Justify this statement with a reason and an example.CBSE 20152 m

Experiences and qualifications are acquired traits: they are gained by an individual during its lifetime through practice or environment. Such traits affect only the body (somatic) cells and cause no change in the DNA of the germ cells. Since only the DNA of germ cells is passed to the next generation, acquired traits are not inherited. Example: a person who builds strong muscles by exercise, or learns to play the sitar, does not have children born with strong muscles or the ability to play.

Short answer Two pea plants, one with round yellow seeds (RRYY) and another with wrinkled green seeds (rryy), are crossed. Write the phenotype and genotype of the F1 progeny. When the F1 plants are self-pollinated, write the phenotypic ratio of the F2 progeny and state what this ratio shows.CBSE 20243 m

Gametes: RY from the RRYY parent, ry from the rryy parent. F1: genotype RrYy, phenotype round yellow seeds (both R and Y are dominant). (1 mark)

F1 selfed: RrYy makes four gamete types, RY, Ry, rY, ry. The Punnett square of 16 gives F2 phenotypes 9 round-yellow : 3 round-green : 3 wrinkled-yellow : 1 wrinkled-green, that is 9 : 3 : 3 : 1. (1 mark)

The ratio shows that seed shape and seed colour are inherited independently of each other: new combinations (round-green and wrinkled-yellow) that were absent in the parents appear in F2. Each trait on its own still gives 3 : 1 (12 round : 4 wrinkled; 12 yellow : 4 green). (1 mark)

Short answer Two pea plants, both with round yellow seeds and genotype RRYy, are crossed. Work out the genotypes and phenotypes of the progeny and state the percentage of each phenotype.Frequently asked3 m

Gametes of RRYy: RY and Ry (every gamete carries R; half carry Y and half y). Cross the two: RRYY, RRYy, RRYy, RRyy in the ratio 1 : 2 : 1. (1 mark)

Phenotypes: RRYY and RRYy are round yellow (3 out of 4); RRyy is round green (1 out of 4). So 75% of the progeny have round yellow seeds and 25% have round green seeds. All are round because both parents are RR. (1 mark)

Reasoning: since R is fixed, only the Y/y pair is segregating, so the cross behaves like a monohybrid Yy × Yy and gives 3 : 1, not 9 : 3 : 3 : 1. (1 mark)

Short answer In human beings there is a 50% probability of the birth of a boy and a 50% probability of the birth of a girl. Justify this statement with the help of a flow chart showing sex determination.Frequently asked3 m

Flow chart: Mother 44 + XX → egg 22 + X (one type). Father 44 + XY → sperm 22 + X and sperm 22 + Y (two types, equal in number). Egg + X sperm → 44 + XX zygote → girl. Egg + Y sperm → 44 + XY zygote → boy. (Chart: 1½ marks)

Justification: half the sperm carry X and half carry Y, because the X and Y separate equally when sperm are formed. Which sperm fertilises the egg is a matter of chance. So the chance of an XX zygote (girl) equals the chance of an XY zygote (boy), 1 : 1 or 50% each. The sex is decided by the father's sperm, not by the mother, who gives X in every case. (1½ marks)

Short answer Different species use different strategies to determine the sex of a newborn individual. Explain with examples.CBSE 20163 m

(i) Environmental: in some reptiles the sex of the young is decided by the temperature at which the fertilised eggs are kept during development; eggs at one temperature give males and at another give females. (1 mark)

(ii) Non-genetic and changeable: in snails, an individual can change its sex during its life, which shows that sex in such animals is not fixed by genes. (1 mark)

(iii) Genetic: in human beings sex is decided by the sex chromosomes. Females are XX and males XY. All eggs carry X; sperm carry X or Y. A child that receives Y from the father is a boy (XY) and one that receives X is a girl (XX). (1 mark)

Short answer Mustard was growing in two fields, A and B. The plants in field A were tall and those in field B were short. Give two probable reasons for this difference and explain which of them can be inherited.CBSE 20223 m

Reason 1, inherited: the plants in the two fields may be of different varieties, carrying different genes for height. Tallness or shortness that comes from genes is an inherited trait and will be passed to the seeds and the next generation. (1½ marks)

Reason 2, acquired: the plants may have the same genes but field B may have poorer soil, less water, less sunlight or less manure, so its plants could not grow to their full height. Height reduced by environment is an acquired trait; it affects only the plants' bodies, not the DNA of their germ cells, and is not inherited. Seeds from field B grown in good soil would give tall plants. (1½ marks)

Long answer How do Mendel's experiments show that (a) traits may be dominant or recessive, and (b) the inheritance of two traits is independent of each other? Draw the crosses.CBSE 20175 m

(a) Mendel crossed pure tall (TT) and pure short (tt) pea plants. F1: all Tt, all tall; no short or intermediate plants. On selfing F1, F2 gave tall and short in the ratio 3 : 1 (genotypes 1 TT : 2 Tt : 1 tt). The trait seen in all of F1 (tall) is dominant; the trait that was hidden in F1 and reappeared in one-quarter of F2 (short) is recessive. Cross: TT × tt → Tt; Tt × Tt → TT, Tt, Tt, tt. (2½ marks)

(b) Mendel crossed plants with round yellow seeds (RRYY) and plants with wrinkled green seeds (rryy). F1: all RrYy, round and yellow. On selfing, F2 contained four phenotypes: 9 round-yellow, 3 round-green, 3 wrinkled-yellow, 1 wrinkled-green (9 : 3 : 3 : 1). Two of these, round-green and wrinkled-yellow, are new combinations not present in either parent. If the traits were linked, only the parental combinations would appear. The new combinations show that seed shape and seed colour are inherited independently; each on its own still gives 3 : 1. Cross: RRYY × rryy → RrYy; RrYy × RrYy with gametes RY, Ry, rY, ry in a 16-box square. (2½ marks)

Long answer (a) What are dominant and recessive traits? Explain with the help of Mendel's monohybrid cross in pea plants. (b) Is it possible that a trait is inherited but may not be expressed? Justify your answer with an example.CBSE 20195 m

(a) A dominant trait is the one that expresses itself in the offspring even when only one copy of its gene is present; a recessive trait expresses itself only when both copies of the gene are recessive. Mendel crossed pure tall (TT) with pure short (tt) peas. All F1 plants (Tt) were tall, so tallness is dominant and shortness recessive. When F1 plants were selfed, F2 was 1 TT : 2 Tt : 1 tt, that is 3 tall : 1 short. The short trait reappeared in F2 in its original form. Chart: P TT × tt, gametes T and t, F1 Tt, Punnett square for F2. (3 marks)

(b) Yes. The F1 plants of the cross above are Tt. They inherited the gene t for shortness from the short parent, but the trait was not expressed because t is recessive and T is present. That the trait was inherited is proved by its reappearance in the F2 generation, where one-quarter of plants (tt) are short. So a trait can be carried and passed on without being seen. (2 marks)

Long answer (a) State the rule Mendel found for the inheritance of a pair of contrasting traits (dominance), using the tall × short cross. Write the phenotypic and genotypic ratios of the F2 generation. (b) Why are traits acquired during the lifetime of an individual not inherited? Give one example.CBSE 20205 m

(a) When two pure parents with contrasting forms of a trait are crossed, only one form, the dominant one, appears in F1; the other, recessive form is hidden and reappears in F2. Tall (TT) × short (tt) gives F1 all Tt, tall. Selfing F1 gives F2 with genotypic ratio 1 TT : 2 Tt : 1 tt and phenotypic ratio 3 tall : 1 short. Draw the chart with gametes and the Punnett square. (3 marks)

(b) Acquired traits arise from changes in the non-reproductive (body) cells of an individual due to its own activity or environment. They do not cause any change in the DNA of the germ cells, and only germ-cell DNA is passed on to the next generation. So acquired traits die with the individual. Example: a person's trained muscles, a scar, or a language learnt are not born into their children; a plant stunted by poor soil gives seeds that grow to full height in good soil. (2 marks)

Long answer Sex of an individual is determined by different factors in various species. Explain with two examples. State how, in human beings, the sex of an individual is largely determined genetically, and show it with a flow chart.CBSE 20225 m

Different species: (i) In some reptiles, the temperature at which the fertilised eggs are kept during development decides whether the young are male or female, so sex is decided by an environmental factor. (ii) In snails, an individual can change its sex during its lifetime, so sex is not fixed by genes. (2 marks)

Humans: sex is decided genetically by the sex chromosomes. Body cells have 23 pairs of chromosomes; 22 pairs are autosomes and the 23rd pair is XX in a woman and XY in a man. The Y chromosome is much shorter than the X. Every egg carries 22 + X. Sperm are of two kinds in equal numbers, 22 + X and 22 + Y. An egg fertilised by an X sperm becomes an XX zygote and a girl; fertilised by a Y sperm it becomes XY and a boy. The child always gets X from the mother, so the father's sperm decides the sex, and since the two sperm types are equal in number, the probability of a boy or a girl is 50% each. (2 marks)

Flow chart: Female 44 + XX → egg 22 + X; Male 44 + XY → sperm 22 + X or 22 + Y; zygotes 44 + XX (girl) and 44 + XY (boy), 1 : 1. (1 mark)

Case-based Gregor Mendel grew pea plants for several years and kept careful counts. He crossed pure tall plants with pure short plants. Every plant of the first generation was tall. He then let these plants self-pollinate and found that among the next generation, about three plants in four were tall and one in four was short. The short plants were just as short as the original short parent. He got the same pattern with other pairs of traits, such as round and wrinkled seeds and violet and white flowers.
(i) Why were all the plants of the first generation tall, although one parent was short?
(ii) Write the genotypes of the parents, the F1 plants and the F2 plants.
(iii) What does the reappearance of short plants in F2 tell us?
(iv) If Mendel had crossed an F1 plant with the original short parent, what ratio of tall to short plants would he expect?
Frequently asked4 m

(i) Because tallness is dominant over shortness. The F1 plants received T from the tall parent and t from the short parent, and one T is enough for the plant to be tall.

(ii) Parents TT and tt; F1 all Tt; F2 1 TT : 2 Tt : 1 tt.

(iii) That the trait for shortness was inherited by the F1 plants and carried along without being expressed; a trait can be inherited but not shown. It also tells us that the two factors did not blend, since the F2 short plants were fully short.

(iv) Tt × tt → Tt and tt in equal numbers, so 1 tall : 1 short (50% each).

Case-based Human body cells contain 46 chromosomes arranged in 23 pairs. Twenty-two of these pairs look the same in men and women. The 23rd pair differs: women have two similar chromosomes called X, while men have one X and one much shorter chromosome called Y. When gametes are formed, each receives only one chromosome from every pair. A couple who already have three daughters are told by a relative that the mother is 'responsible' for not having a son.
(i) How many chromosomes does a human sperm carry, and of what two kinds can it be?
(ii) What are the 22 pairs of chromosomes that are alike in both sexes called?
(iii) Is the relative correct? Give the reason.
(iv) What is the probability that the couple's fourth child will be a boy?
Frequently asked4 m

(i) 23 chromosomes: 22 autosomes plus one sex chromosome, so a sperm is either 22 + X or 22 + Y.

(ii) Autosomes.

(iii) No. Every egg carries an X, so the mother contributes X to every child. The sex of the child depends on whether the sperm that fertilises the egg carries X (girl) or Y (boy), and that is a matter of chance. Neither parent can be held responsible.

(iv) 50% (½). Each fertilisation is an independent event; the previous three daughters do not change the chance, because half the sperm carry X and half carry Y every time.

Test yourselfPractice quiz

Marks lost every yearCommon mistakes

  • Writing 9 : 3 : 3 : 1 as the F1 ratio of a dihybrid cross. F1 is all one type (RrYy, round yellow); 9 : 3 : 3 : 1 is the F2 phenotype ratio. The examiner deducts the ratio mark straight away.
  • Mixing up the genotype ratio (1 : 2 : 1) and the phenotype ratio (3 : 1) of a monohybrid F2, or writing only one when the question asks for both. Label each ratio by name.
  • Drawing a cross without gametes, or without labelling P, F1 and F2. The marking scheme gives separate marks for gametes and for the correct generation labels.
  • Saying the mother decides, or that the father is 'responsible' for, the sex of the child. The mother always gives X; the father's sperm carries X or Y; which sperm fertilises the egg is chance. All three sentences are needed.
  • Claiming that variation helps the individual survive. NCERT's point is that variation increases the survival chances of the species when the environment changes; for an individual it may be useless or even harmful.
  • Answering 'acquired traits are not inherited' without the reason. The mark is for 'because they do not change the DNA of the germ cells'.
  • Applying 9 : 3 : 3 : 1 mechanically when the parents are not both double hybrids (for example RRYy × RRYy). Write the gametes and work the square; here the answer is 3 : 1.
  • Writing that Tt plants are of medium height, or that the t gene is lost in F1. Tt is fully tall because T is dominant, and t is carried to the next generation unchanged.
  • Treating the blood-group in-text question as if it had an answer of A or O. The correct answer is that the information is not enough, with the reason that both dominance possibilities fit the family.

How to prepareStrategy for this chapter

This is a short chapter with a long exam shadow, so prepare it by question type rather than by reading it end to end. Start with the two crosses. Practise drawing the monohybrid chart (parents, gametes, F1, Punnett square, both F2 ratios) until you can do it in under two minutes, then the dihybrid chart with its 16 boxes and the 9 : 3 : 3 : 1 count. Once the standard crosses are automatic, do five non-standard ones: Tt × tt, TT × Tt, RRYy × RRYy, and the NCERT TtWW question, because the board increasingly changes the parents and expects you to work the square rather than quote a ratio.

Next, the sex-determination flow chart. Draw it from memory with the numbers (44 + XX, 44 + XY, 22 + X, 22 + Y) and the three conclusions written under it: mother always gives X, father's sperm decides, 50 : 50 by chance. This one chart answers a 2-mark, a 3-mark and a 5-mark question.

Then the reasoning questions, which are short but need exact wording: why acquired traits are not inherited (germ-cell DNA unchanged), why a trait can be inherited yet not expressed (recessive, carried in a hybrid), why the 60% trait arose before the 10% trait, and why variation helps the species rather than the individual (the heat-wave bacteria). Write each answer once in full and check it against the NCERT sentence.

Finally, read 8.2.3 once more for the gene-enzyme-hormone chain and the single-set-in-germ-cells argument; these are the parts students skip and the parts that appear as assertion-reason items. On the day, a 3-mark cross question should take about five minutes including the chart, and a 5-mark Mendel question about eight.

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