Class 11 · Biology · Chapter 12
Respiration in Plants
The chapter follows one molecule of glucose from the cytoplasm to the mitochondrion: glycolysis, the two fermentations, oxidative decarboxylation of pyruvate, the citric acid cycle, the electron transport system with chemiosmosis, and then the bookkeeping of ATP, the amphibolic nature of the pathway and the respiratory quotient. It is the base for Class 12 boards and NEET; the exam wants exact enzyme names, exact sites, exact counts of ATP, NADH and FADH2, and the three NCERT figures drawn from memory.
Before you startWhat the board asks from this chapter
Class 11 Biology is a 70-mark theory paper set by the school on the CBSE pattern. Respiration in Plants sits in Unit IV, Plant Physiology, which carries about 12 marks shared with Photosynthesis in Higher Plants and Plant Growth and Development. In a typical school final this chapter alone brings 5 to 8 marks: one or two 1-mark items (an MCQ on the site of a step, the enzyme of a step, RQ of a substrate, or the ATP yield of NADH), a 2-mark or 3-mark question on fermentation versus aerobic respiration, the assumptions of the balance sheet, RQ or the amphibolic pathway, and often a 5-mark question on glycolysis, the citric acid cycle or the ETS with a labelled diagram. In NEET it is a steady two-question chapter, with the questions lifted almost word for word from NCERT sentences and figures.
| Question type | Marks | Usually asked |
|---|---|---|
| MCQ | 1 | Site of glycolysis (cytoplasm) and of the citric acid cycle (mitochondrial matrix) and of the ETS (inner mitochondrial membrane); the enzyme of a named step (hexokinase, phosphofructokinase, aldolase, enolase, pyruvate kinase, pyruvic acid decarboxylase, alcohol dehydrogenase, lactate dehydrogenase, pyruvic dehydrogenase, citrate synthase, succinate dehydrogenase, cytochrome c oxidase); the step of GTP formation (succinyl-CoA to succinic acid); the number of NADH and FADH2 per turn of the cycle; ATP from one NADH (3) and one FADH2 (2); the final electron acceptor (oxygen); the RQ of carbohydrates (1), fats (about 0.7) and proteins (about 0.9); the alcohol concentration at which yeast dies (about 13 per cent); the molecule common to breakdown of fats, carbohydrates and proteins (acetyl CoA); who discovered the cycle (Hans Krebs, 1937) and the pathway (Embden, Meyerhof, Parnas). |
| Assertion–Reason | 1 | Fermentation yields little energy because glucose is only partly oxidised; oxygen does not take part in the Krebs cycle directly yet aerobic respiration needs it because oxygen is the final hydrogen acceptor; RQ of fats is below one; the respiratory pathway is amphibolic; glycolysis needs no oxygen; ATP synthase is complex V; plants do not need specialised breathing organs; the net gain is 36 not 38 ATP. |
| Very short answer | 2 | Define RQ and give its value for fats; two differences between fermentation and aerobic respiration; what is oxidative decarboxylation; what is substrate-level phosphorylation with one example from glycolysis and one from the citric acid cycle; roles of F0 and F1; why is the pathway called amphibolic; what are respiratory substrates; name the enzyme and coenzyme of the link reaction; why do plants not need breathing organs (two reasons); the fate of pyruvate under three conditions. |
| Short answer | 3 | Explain fermentation in yeast with the equation and the two enzymes; explain oxidative phosphorylation and chemiosmosis; the four assumptions of the respiratory balance sheet; distinguish glycolysis from the citric acid cycle (three points); significance of step-wise release of energy; RQ calculation for tripalmitin; the overall reaction of the citric acid cycle; the three fates of pyruvic acid with the enzyme of each. |
| Long answer | 5 | Describe glycolysis with the schematic and mark the two ATP-consuming and two ATP-forming steps; describe the citric acid cycle with the schematic and the tally per acetyl CoA; describe the ETS with the labelled diagram of the five complexes and the role of oxygen; the NCERT exercise 12.1 and 12.7 sets of differences (respiration versus combustion, glycolysis versus Krebs cycle, aerobic respiration versus fermentation, aerobic versus anaerobic respiration, glycolysis versus citric acid cycle); prepare the balance sheet and show how 36 ATP arise. |
| Case-based | 4 | A passage on a germinating-seed respirometer experiment giving different RQ values, on a brewery or bread dough where yeast ferments, on an athlete's muscle cramp, or on a mitochondrion drawing with sites to identify, followed by four sub-questions. |
Hot topics, in order
- Glycolysis: the ten steps, the two ATP-using and two ATP-making steps, net 2 ATP and 2 NADH (Fig. 12.1)
- Fermentation: alcoholic and lactic acid, the enzymes, why less than 7 per cent of energy is released, yeast dying at about 13 per cent alcohol (Fig. 12.2)
- Citric acid (Krebs, TCA) cycle: the schematic, the GTP step, 3 NADH + 1 FADH2 per turn and the overall equation (Fig. 12.3)
- Electron transport system: complexes I to V, ubiquinone and cytochrome c as mobile carriers, oxygen as the final acceptor (Fig. 12.4)
- Oxidative phosphorylation and chemiosmosis: F0, F1, 2H+ per ATP, 3 ATP per NADH and 2 per FADH2
- Respiratory balance sheet: the four assumptions and the net 36 ATP per glucose
- Amphibolic pathway: where fats, glycerol and amino acids enter, and what is withdrawn for synthesis (Fig. 12.5)
- Respiratory quotient: definition, RQ of carbohydrates, fats (tripalmitin 0.7) and proteins
The whole chapter, in orderNotes
01 Introduction: why cells respire and what they respire
Every living cell needs energy to grow, divide, transport substances across membranes and make its own molecules. That energy comes from the oxidation of macromolecules in the cell, and the process is called cellular respiration. The compounds that are oxidised are the respiratory substrates: carbohydrates, proteins, fats and organic acids. Glucose is the most common respiratory substrate, and the exam expects you to say so in those exact words. In plants, sucrose made in the leaf is first split by the enzyme invertase into glucose and fructose, and both enter the pathway.
Write the overall equation once and remember its shape:
C6H12O6 + 6O2 → 6CO2 + 6H2O + Energy
Two things about this equation matter for marks. First, it is a summary, not a single step. Glucose is broken down in a long series of small enzyme-catalysed steps, each releasing a little energy. NCERT stresses that the energy is not released free into the cell in a single step; it is released in a series of slow, enzyme-controlled steps and trapped as ATP. Combustion releases it all at once as heat and light, respiration does not. The step-wise release is what allows some of the energy to be trapped rather than lost as heat. Second, the energy that is released is not used directly. It is used to make ATP (adenosine triphosphate) from ADP and inorganic phosphate, and ATP is broken down wherever and whenever the cell needs energy. That is why ATP is called the energy currency of the cell.
The chapter therefore has one story: how does glucose become CO2 and water, and how many ATP does the cell get on the way? Keep the sites in mind from the start. Glycolysis happens in the cytoplasm of every cell, whether it has oxygen or not; everything after pyruvic acid that needs oxygen happens inside the mitochondrion, the link reaction and the citric acid cycle in the matrix and the electron transport system on the inner membrane. Almost every 1-mark question in this chapter is a question about a site or an enzyme, so learn the place of each step as you learn the step.
02 12.1 Do Plants Breathe?
Animals breathe: they have lungs or gills that move gases in and out. Plants do not. Yet plants need O2 for respiration and give out CO2, so gas exchange must happen somehow. The NCERT answer is that plants have no specialised organs for gas exchange, and use stomata on leaves and young stems and lenticels on woody stems and roots. Each plant part takes care of its own gas exchange needs; there is no transport of gases from one organ to another, and only a very small quantity of gas is carried by the transport system.
Why can plants get away without lungs? The chapter gives reasons you should be able to list as a 2-mark or 3-mark answer:
- Each part of the plant takes care of its own gas-exchange needs, so there is no need to move gases around the body.
- Plants do not present great demands for gas exchange. Roots, stems and leaves respire at rates far lower than animals do.
- During photosynthesis, O2 is released within the cell, so the leaf cells are supplied with oxygen while they are photosynthesising.
- Cells that are living are located close to the surface of the plant. In stems the living cells are arranged in thin layers under the bark, and they have openings (lenticels); in leaves most cells are near the surface anyway.
- A large part of the bulky plant body is made of dead cells (wood) or loosely packed parenchyma with large intercellular spaces, so gases diffuse easily through the plant body. The distance a gas has to diffuse is never very large.
The examiner also likes the distinction between breathing and respiration. Breathing is the physical process of taking in O2 and giving out CO2, whatever organ does it. Respiration is the chemical process inside the cell where the substrate is oxidised and energy is trapped as ATP. Plants respire in every living cell, but they do not breathe in the animal sense; they simply let gases diffuse in and out through stomata and lenticels.
One more fact that gets asked: because glycolysis happens in the cytoplasm and needs no oxygen, all living cells, plant or animal, aerobic or anaerobic, carry out glycolysis. Only the fate of pyruvic acid depends on whether oxygen is available.
03 12.2 Glycolysis
The name means splitting of sugar (glycos, sugar; lysis, splitting). The scheme was worked out by Gustav Embden, Otto Meyerhof and J. Parnas, so it is also called the EMP pathway. It is the partial oxidation of one molecule of glucose (6C) to two molecules of pyruvic acid (3C). It takes place in the cytoplasm, needs no oxygen and occurs in all living organisms. In anaerobic organisms it is the only process in respiration.
NCERT describes ten steps, each with an enzyme, and the marking scheme rewards the schematic in Fig. 12.1 drawn in order. Learn it as a story in three parts.
Part 1, spend two ATP to activate the sugar. Glucose is phosphorylated by hexokinase to glucose-6-phosphate (one ATP used). This isomerises to fructose-6-phosphate. Phosphofructokinase then adds a second phosphate using a second ATP to give fructose 1,6-bisphosphate. These are the only two ATP-consuming steps; NCERT names them as the conversion of glucose to glucose 6-phosphate and of fructose 6-phosphate to fructose 1,6-bisphosphate.
Part 2, split the sugar. Aldolase splits fructose 1,6-bisphosphate into two 3-carbon molecules, dihydroxyacetone phosphate (DHAP) and 3-phosphoglyceraldehyde (PGAL). DHAP is isomerised to PGAL, so from here on everything happens twice per glucose.
Part 3, oxidise and harvest. PGAL is oxidised and phosphorylated to 1,3-bisphosphoglycerate (BPGA); the two hydrogen atoms (redox equivalents) removed from PGAL are transferred to NAD+, forming NADH + H+. BPGA gives up one phosphate to ADP and becomes 3-phosphoglyceric acid (3-PGA); this is an ATP-forming step. 3-PGA rearranges to 2-phosphoglycerate, which loses a water molecule (enolase) to become phosphoenolpyruvate (PEP). PEP transfers its phosphate to ADP (pyruvate kinase) to give pyruvic acid and the second ATP. Both ATP-forming steps are examples of substrate-level phosphorylation: the phosphate comes straight from a substrate molecule, not from an electron transport chain.
Now count. Two ATP are used in part 1. Four ATP are made in part 3 (two steps, each occurring twice). Net gain: 2 ATP and 2 NADH + H+ per glucose, plus two pyruvic acid. The exam asks this count in every form.
Pyruvic acid is the key product of glycolysis, and its fate depends on the cell and on oxygen. NCERT names three major ways: lactic acid fermentation, alcoholic fermentation and aerobic respiration. Fermentation happens under anaerobic conditions in many prokaryotes and unicellular eukaryotes; aerobic respiration needs oxygen and, in eukaryotes, mitochondria.
04 12.3 Fermentation
When there is no oxygen, pyruvic acid cannot enter the mitochondrion for complete oxidation. The cell then does the minimum needed to keep glycolysis running: it reoxidises the NADH + H+ made in glycolysis back to NAD+, because without NAD+ the PGAL step would stop and no more ATP could be made. This incomplete oxidation of glucose is called fermentation, and NCERT describes two kinds.
Alcoholic fermentation in yeast. Pyruvic acid is first decarboxylated to acetaldehyde by pyruvic acid decarboxylase, releasing CO2. Then acetaldehyde is reduced by alcohol dehydrogenase to ethanol, and NADH + H+ is oxidised to NAD+ in the process. Overall, one glucose gives two ethanol and two CO2. This is the reaction that makes bread rise and makes beer and wine.
Lactic acid fermentation in some bacteria and in animal muscle during heavy exercise, when oxygen is inadequate. Pyruvic acid is reduced directly to lactic acid by lactate dehydrogenase, again oxidising NADH + H+ to NAD+. No CO2 is released. In both cases the reducing agent is NADH + H+, which is reoxidised to NAD+; this recycling is the point of fermentation.
Three exam facts about the yield:
- In both fermentations very little energy is released: less than seven per cent of the energy in glucose is released, and not all of it is trapped as high-energy bonds of ATP. The net gain is only the 2 ATP of glycolysis.
- Fermentation is a partial breakdown of glucose; aerobic respiration degrades glucose completely to CO2 and H2O.
- The products are toxic. Yeasts poison themselves to death when the concentration of alcohol reaches about 13 per cent, which is why naturally fermented beverages are not stronger than that; spirits are made by distillation.
NCERT's Fig. 12.2 summarises the major pathways of anaerobic respiration: glucose → pyruvic acid, and then three arrows, to lactic acid (lactate dehydrogenase), to ethanol + CO2 (pyruvic acid decarboxylase then alcohol dehydrogenase) and to acetyl CoA + CO2 for aerobic respiration. Draw it for any question on the fate of pyruvic acid.
NCERT treats fermentation and anaerobic respiration together, and the comparison the examiner cares about is with aerobic respiration: no oxygen needed, no mitochondrion, no complete oxidation, no ETS, NADH oxidised by the organic acceptor (pyruvate or acetaldehyde) rather than by oxygen, and only 2 ATP.
05 12.4 Aerobic Respiration: entry into the mitochondrion and the link reaction
Aerobic respiration is the process that leads to the complete oxidation of organic substances in the presence of oxygen, releasing CO2, water and a large amount of energy. In eukaryotes it happens in the mitochondria, so the pyruvic acid made in the cytoplasm must first be transported into the mitochondrial matrix. The chapter describes two crucial events that follow: the complete oxidation of pyruvate by step-wise removal of all the hydrogen atoms, leaving three molecules of CO2; and the passing of those electrons to molecular O2 with simultaneous synthesis of ATP. The first happens in the matrix, the second on the inner membrane.
The link reaction (oxidative decarboxylation of pyruvate). Inside the matrix, pyruvic acid (3C) undergoes oxidative decarboxylation by a complex set of reactions catalysed by pyruvic dehydrogenase. The reaction needs the participation of several coenzymes, including NAD+ and Coenzyme A. One carbon leaves as CO2, the remaining two-carbon acetyl group is attached to CoA to give acetyl CoA, and NAD+ is reduced to NADH + H+.
Pyruvic acid + CoA + NAD+ → Acetyl CoA + CO2 + NADH + H+ (pyruvic dehydrogenase, Mg2+)
Since one glucose gives two pyruvic acid, this step produces 2 NADH + H+ and 2 CO2 per glucose. Call it oxidative decarboxylation in the exam: oxidative because NAD+ is reduced (pyruvate is oxidised), decarboxylation because CO2 is removed. Acetyl CoA then enters the cyclic pathway, the tricarboxylic acid cycle, described next.
Why is acetyl CoA important beyond this chapter? It is the molecule where the breakdown of fats, carbohydrates and proteins meet: fatty acids are broken down to acetyl CoA, several amino acids are converted to it, and glucose reaches it through pyruvate. NEET has asked exactly this twice: the biomolecule common to respiration-mediated breakdown of fats, carbohydrates and proteins is acetyl CoA, not pyruvic acid.
Keep the sites straight for the whole of aerobic respiration: glycolysis in the cytoplasm; link reaction and citric acid cycle in the mitochondrial matrix; ETS and oxidative phosphorylation on the inner mitochondrial membrane. Draw a mitochondrion once with these three labels and the 1-mark site questions stop being a risk.
06 12.4.1 Tricarboxylic Acid Cycle (Citric Acid Cycle, Krebs Cycle)
The cycle was first elucidated by Hans Krebs in 1937, hence Krebs cycle. Because the first product, citric acid, has three carboxyl groups it is also the tricarboxylic acid (TCA) cycle or citric acid cycle. It runs in the mitochondrial matrix.
Entry. Acetyl CoA (2C) condenses with oxaloacetic acid (OAA, 4C) and water to give citric acid (6C), catalysed by citrate synthase; a molecule of CoA is released and goes back to pick up another acetyl group. Citrate is then isomerised to isocitrate.
Two decarboxylations. Isocitrate loses one CO2 and is oxidised (NAD+ → NADH + H+) to α-ketoglutaric acid (5C). α-Ketoglutaric acid loses a second CO2, is oxidised again (a second NADH + H+) and joins CoA to become succinyl-CoA (4C). These are the two CO2 molecules of one turn; together with the CO2 of the link reaction they account for the three carbons of one pyruvate.
The GTP step. Succinyl-CoA is converted to succinic acid and CoA is released; the energy of the thioester bond is used to make a molecule of GTP from GDP and Pi. This is a substrate-level phosphorylation, the only one in the cycle. In a coupled reaction GTP is converted to GDP with simultaneous synthesis of ATP from ADP, so it is counted as one ATP.
Regeneration of OAA. Succinic acid is oxidised to fumaric acid by succinate dehydrogenase; here the acceptor is FAD, which becomes FADH2 (the only FADH2 of the cycle). Fumaric acid takes up water to give malic acid, and malic acid is oxidised (third NADH + H+) to oxaloacetic acid, which is ready to accept the next acetyl CoA. The continued oxidation of acetyl CoA therefore needs the continued replenishment of OAA and the regeneration of NAD+ and FAD.
Tally per turn (per acetyl CoA): 2 CO2, 3 NADH + H+, 1 FADH2, 1 GTP (= 1 ATP). Per glucose the cycle turns twice, so 4 CO2, 6 NADH + H+, 2 FADH2, 2 ATP. NCERT gives the summary equation for one pyruvic acid, which includes the link reaction:
Pyruvic acid + 4NAD+ + FAD + 2H2O + ADP + Pi → 3CO2 + 4NADH + 4H+ + FADH2 + ATP
Note what the cycle does not do: no oxygen is used directly, and only one ATP is made by substrate-level phosphorylation. Its real output is reduced coenzymes, NADH + H+ and FADH2, whose oxidation in the ETS produces most of the cell's ATP. Also note that the cycle needs oxygen indirectly, because the NAD+ and FAD it requires are regenerated only when the ETS passes their electrons to oxygen.
07 12.4.2 Electron Transport System (ETS) and Oxidative Phosphorylation
So far the energy of glucose has been parked in NADH + H+ and FADH2. The electron transport system on the inner mitochondrial membrane releases and uses that energy: electrons are passed from one carrier to another and finally to oxygen, and the energy released on the way is used to make ATP. This is the metabolic pathway through which the electron passes from one carrier to another.
The carriers, in order (NCERT Fig. 12.4).
- Complex I, NADH dehydrogenase. Electrons from NADH produced in the mitochondrial matrix during the citric acid cycle are oxidised here and passed to ubiquinone (UQ), a mobile carrier within the inner membrane.
- Complex II, succinate dehydrogenase. Ubiquinone also receives reducing equivalents from FADH2, which is generated during the oxidation of succinate in the citric acid cycle. This is why the FADH2 electrons skip complex I and yield fewer ATP.
- Complex III, cytochrome bc1 complex. Reduced ubiquinone (ubiquinol) is oxidised and the electrons are transferred to cytochrome c.
- Cytochrome c is a small protein attached to the outer surface of the inner membrane; it is a mobile carrier of electrons between complex III and complex IV.
- Complex IV, cytochrome c oxidase. Contains cytochromes a and a3 and two copper centres. It hands the electrons to molecular oxygen, the final acceptor, which is reduced to water.
Where the ATP comes from. When the electrons pass through the chain, they are coupled to ATP synthase (complex V) for the production of ATP from ADP and Pi. The number of ATP depends on the electron donor: oxidation of one NADH gives 3 ATP, of one FADH2 gives 2 ATP.
Chemiosmosis and ATP synthase. As electrons move through the complexes, protons are pumped from the matrix into the intermembrane space, creating a proton gradient across the inner membrane. ATP synthase has two parts. F1 is the headpiece, a peripheral membrane protein complex that contains the site for synthesis of ATP from ADP and Pi. F0 is an integral membrane protein complex that forms the channel through which protons cross the inner membrane. The passage of protons through the channel is coupled to the catalytic site of F1. NCERT's number: for each ATP produced, 2H+ pass through F0 from the intermembrane space to the matrix down the electrochemical proton gradient. Because the ATP is made by oxidation of the coenzymes with oxygen as the acceptor, the process is called oxidative phosphorylation, as opposed to photophosphorylation in the chloroplast where the energy comes from light.
Role of oxygen. Oxygen is used only at the end of the pathway, yet it is essential for the whole of aerobic respiration. NCERT puts it simply: the role of oxygen is limited to the terminal stage, but its presence is vital because it drives the whole process by removing hydrogen from the system. Oxygen acts as the final hydrogen (electron) acceptor. Without it the carriers stay reduced, NAD+ and FAD are not regenerated, and the citric acid cycle stops.
08 12.5 The Respiratory Balance Sheet
The balance sheet is the exam's favourite arithmetic. NCERT is honest that the calculation is theoretical and rests on four assumptions that are not really valid in a living system; the assumptions themselves are a 2-mark or 3-mark question (NCERT exercise 12.8).
- There is a sequential, orderly pathway functioning, with one substrate forming the next and with glycolysis, TCA cycle and ETS following one after another.
- The NADH synthesised in glycolysis is transferred into the mitochondria and undergoes oxidative phosphorylation.
- None of the intermediates in the pathway are utilised to synthesise any other compound.
- Only glucose is being respired; no other alternative substrates enter the pathway at any of the intermediary stages.
In reality all pathways work simultaneously, substrates enter and leave at many points, ATP is used as and when needed, and enzyme rates change. Still, the calculation gives a useful figure.
The tally per glucose.
- Glycolysis (cytoplasm): 2 ATP (substrate level) + 2 NADH + H+.
- Link reaction (matrix): 2 NADH + H+.
- Citric acid cycle, two turns (matrix): 2 ATP via GTP + 6 NADH + H+ + 2 FADH2.
- Totals of reduced coenzymes: 10 NADH + H+ and 2 FADH2.
- ETS (inner membrane): 10 × 3 = 30 ATP from NADH, 2 × 2 = 4 ATP from FADH2.
Adding: 2 + 2 + 30 + 4 = 38 ATP if every NADH gives three ATP. NCERT states that there can be a net gain of 36 ATP molecules during aerobic respiration of one molecule of glucose; the difference is that the 2 NADH made in the cytoplasm during glycolysis have to be moved into the mitochondrion, and the transport costs the equivalent of 2 ATP. Give 36 as the NCERT answer and explain the 38 when asked to show working.
Fermentation versus aerobic respiration, the comparison NCERT draws at the end of this section, is asked every year:
- Fermentation is a partial breakdown of glucose; in aerobic respiration glucose is completely degraded to CO2 and H2O.
- Fermentation gives a net gain of only 2 ATP per glucose; aerobic respiration gives many more, 36.
- In fermentation NADH is oxidised to NAD+ rather slowly, by pyruvate or acetaldehyde; in aerobic respiration it is oxidised vigorously by the ETS with oxygen as the acceptor.
09 12.6 Amphibolic Pathway
Glucose is the favoured substrate, but cells respire other things too, and they enter the same pathway at different points. NCERT's Fig. 12.5 (interrelationship among metabolic pathways) is the picture to remember.
- Fats are first broken down into glycerol and fatty acids. Fatty acids are degraded to acetyl CoA, which enters the citric acid cycle. Glycerol enters glycolysis as PGAL (3-phosphoglyceraldehyde).
- Proteins are degraded by proteases to amino acids, and the amino acids, after deamination, enter at different points: some as pyruvate, some as acetyl CoA, some as intermediates of the citric acid cycle such as α-ketoglutaric acid or oxaloacetic acid.
- Carbohydrates other than glucose (starch, sucrose, fructose) are converted to glucose or its phosphates and enter glycolysis.
So far this is catabolism, the breakdown of molecules. The important point is that the same pathway also runs the other way. When the organism needs to synthesise fatty acids, acetyl CoA is withdrawn from the respiratory pathway. Many amino acids are made from intermediates of the citric acid cycle. Glycerol for fat synthesis comes from PGAL. That is anabolism, biosynthesis, using respiratory intermediates as starting material.
Since the respiratory pathway is involved in both breakdown and synthesis, it is better to call it an amphibolic pathway rather than a purely catabolic one. That single sentence, with two examples on each side, is the model 2-mark answer for NCERT exercise 12.9. For a 3-mark version, add that this is why a cell cannot stop respiring even when it has plenty of ATP: the intermediates are needed as building blocks, which is also assumption 3 of the balance sheet being violated in real life.
Two definitions to keep separate. Catabolic pathways break large molecules down and release energy; anabolic pathways build molecules and use energy; amphibolic pathways do both. Respiration is often described as catabolic in short answers (and 'catabolic' is the accepted answer to 'is respiration catabolic or anabolic'), but when the question uses the word amphibolic, the examiner wants the dual role explained.
10 12.7 Respiratory Quotient
During aerobic respiration O2 is consumed and CO2 is released. The ratio of the volume of CO2 evolved to the volume of O2 consumed in respiration is called the respiratory quotient (RQ) or respiratory ratio.
RQ = volume of CO2 evolved / volume of O2 consumed
The value depends on the respiratory substrate, and the exam asks the three standard cases.
Carbohydrates, RQ = 1. From the overall equation, 6 O2 consumed and 6 CO2 evolved, so RQ = 6CO2/6O2 = 1.0.
Fats, RQ less than 1. Fats contain very little oxygen relative to carbon and hydrogen, so they need extra O2 to oxidise their hydrogen, and less CO2 comes out per O2 used. NCERT's example is tripalmitin:
2(C51H98O6) + 145O2 → 102CO2 + 98H2O + energy
RQ = 102CO2/145O2 = 0.7. Check the arithmetic once so you can reproduce it: 102 ÷ 145 = 0.703, written as 0.7.
Proteins, RQ about 0.9. NCERT states that when proteins are the respiratory substrate the ratio would be about 0.9.
Two qualifications the examiner may probe. First, in living organisms pure substrates are rarely used alone; the RQ of a tissue reflects a mixture. Second, RQ is defined for aerobic respiration; in anaerobic conditions (fermentation) CO2 is released without O2 being consumed, so the ratio is not meaningful (it would tend to infinity). Case-based questions build on this with a germinating-seed experiment: starchy seeds such as wheat give RQ close to 1, oily seeds such as castor give a value below 1, and a seed sealed without oxygen releases CO2 without consuming O2.
Why does RQ matter beyond the number? Measuring it tells a physiologist which substrate a tissue is burning, which is useful in studying germinating seeds, ripening fruit or a stressed plant. But for the exam the definition, the formula, the three values and the tripalmitin calculation are the four things to have ready.
VocabularyKey terms
Keep this on one pageFacts and values to remember
| Name | Expression | Notes |
|---|---|---|
| Overall aerobic respiration | C6H12O6 + 6O2 → 6CO2 + 6H2O + Energy | A summary of many enzyme steps; the step-wise release is what separates respiration from combustion. |
| Sites | Glycolysis: cytoplasm. Link reaction and citric acid cycle: mitochondrial matrix. ETS and oxidative phosphorylation: inner mitochondrial membrane. Fermentation: cytoplasm. | The single most common 1-mark question in the chapter. |
| Glycolysis net | Glucose → 2 pyruvic acid + 2 ATP (net) + 2 NADH + H+; ATP used at hexokinase and phosphofructokinase steps; ATP made at BPGA → 3-PGA and PEP → pyruvate | Gross 4 ATP, minus 2 spent. Aldolase splits F-1,6-BP into DHAP and PGAL; enolase makes PEP; pyruvate kinase makes pyruvate. |
| Three fates of pyruvic acid | Lactic acid (lactate dehydrogenase, bacteria and muscle); ethanol + CO2 (pyruvic acid decarboxylase then alcohol dehydrogenase, yeast); acetyl CoA + CO2 (pyruvic dehydrogenase, aerobic, matrix) | NCERT Fig. 12.2. Fermentation releases under 7 per cent of the energy in glucose; yeast dies at about 13 per cent alcohol. |
| Link reaction | Pyruvic acid + CoA + NAD+ → Acetyl CoA + CO2 + NADH + H+ | Pyruvic dehydrogenase with Mg2+; coenzymes NAD+ and CoA; twice per glucose. |
| Citric acid cycle per turn | Acetyl CoA + OAA → citrate → isocitrate → α-ketoglutarate → succinyl-CoA → succinate → fumarate → malate → OAA; yields 2 CO2, 3 NADH + H+, 1 FADH2, 1 GTP | Citrate synthase starts it; GTP at succinyl-CoA → succinate; FADH2 at succinate → fumarate (succinate dehydrogenase); NADH at isocitrate, α-ketoglutarate and malate steps. Hans Krebs, 1937. |
| NCERT summary per pyruvate | Pyruvic acid + 4NAD+ + FAD + 2H2O + ADP + Pi → 3CO2 + 4NADH + 4H+ + FADH2 + ATP | Includes the link reaction NADH. 15 ATP per pyruvate on the 3/2 rule. |
| ETS order | Complex I (NADH dehydrogenase) → UQ ← Complex II (succinate dehydrogenase); UQ → Complex III (cytochrome bc1) → cytochrome c → Complex IV (cytochrome c oxidase, cyt a, a3, 2 Cu centres) → O2 → H2O; Complex V = ATP synthase | Oxygen is the final hydrogen (electron) acceptor; it drives the process by removing hydrogen from the system. |
| ATP per coenzyme and per proton | 1 NADH → 3 ATP; 1 FADH2 → 2 ATP; 2H+ through F0 per ATP | F1 headpiece holds the ATP-synthesising site; F0 forms the proton channel. |
| Balance sheet | 2 (glycolysis) + 2 (GTP) + 10 NADH × 3 + 2 FADH2 × 2 = 38; net 36 after 2 ATP to move cytoplasmic NADH into the mitochondrion | Four assumptions: sequential pathway; glycolytic NADH enters mitochondria; no intermediate withdrawn; only glucose respired. |
| Fermentation vs aerobic | Partial vs complete oxidation; 2 vs 36 ATP; NADH oxidised slowly by pyruvate/acetaldehyde vs vigorously by O2 through the ETS | NCERT's three-point comparison at the end of 12.5. |
| Amphibolic entries | Fatty acids → acetyl CoA; glycerol → PGAL; amino acids → pyruvate / acetyl CoA / TCA intermediates; withdrawals: acetyl CoA for fatty acids, TCA intermediates for amino acids | NCERT Fig. 12.5. Catabolism and anabolism through the same pathway. |
| Respiratory quotient | RQ = volume CO2 evolved / volume O2 consumed; carbohydrate 1.0; tripalmitin 102/145 = 0.7; protein about 0.9 | 2(C51H98O6) + 145O2 → 102CO2 + 98H2O. |
| Why plants need no breathing organs | Each part meets its own need; low demand, rates far below animals; O2 released inside photosynthesising cells; living cells near the surface; large air spaces and dead cells in the bulk | Gas exchange through stomata and lenticels. |
Practise with a pencilDiagrams that earn marks
Steps of glycolysis (NCERT Fig. 12.1)
Draw a vertical flow chart. Glucose at the top; arrow down with 'ATP → ADP, hexokinase' to glucose-6-phosphate; arrow to fructose-6-phosphate; arrow with 'ATP → ADP, phosphofructokinase' to fructose 1,6-bisphosphate. Split the arrow (aldolase) into two boxes side by side, dihydroxyacetone phosphate and 3-phosphoglyceraldehyde, joined by a double-headed arrow (isomerase). From PGAL continue down: '2NAD+ → 2NADH + 2H+' to 1,3-bisphosphoglycerate; '2ADP → 2ATP' to 3-phosphoglycerate; arrow to 2-phosphoglycerate; 'H2O removed, enolase' to phosphoenolpyruvate; '2ADP → 2ATP, pyruvate kinase' to pyruvic acid. Write 'cytoplasm' in a corner and 'net gain: 2 ATP, 2 NADH' at the bottom. Marking points: the two ATP-using steps, the NADH step, the two ATP-forming steps and the split into two 3C molecules.
Major pathways of anaerobic respiration: fates of pyruvic acid (NCERT Fig. 12.2)
Glucose at the top with an arrow labelled 'glycolysis (cytoplasm)' down to pyruvic acid in the centre. From pyruvic acid draw three arrows. Left: 'lactate dehydrogenase, NADH + H+ → NAD+' to lactic acid, labelled 'some bacteria, animal muscle'. Middle: 'pyruvic acid decarboxylase, CO2 released' to acetaldehyde, then 'alcohol dehydrogenase, NADH + H+ → NAD+' to ethanol, labelled 'yeast, anaerobic'. Right: 'pyruvic dehydrogenase, CO2 released, NAD+ → NADH + H+' to acetyl CoA, labelled 'aerobic, mitochondrial matrix', with an arrow onward to the citric acid cycle. Marking points: three products, three enzymes, where CO2 is released, where NADH is reoxidised.
The citric acid cycle (NCERT Fig. 12.3)
Draw a large circle. At the top, acetyl CoA (2C) entering, meeting oxaloacetic acid (4C) with H2O, arrow 'citrate synthase, CoA released' to citric acid (6C). Going clockwise: isocitrate; then arrow with 'CO2' out and 'NAD+ → NADH + H+' to α-ketoglutaric acid (5C); arrow with 'CO2' out, 'NAD+ → NADH + H+' and 'CoA in' to succinyl-CoA (4C); arrow with 'GDP + Pi → GTP, CoA out' to succinic acid; arrow with 'FAD → FADH2' to fumaric acid; arrow with 'H2O' to malic acid; arrow with 'NAD+ → NADH + H+' back to oxaloacetic acid. Beside the circle write 'mitochondrial matrix' and the tally per turn: 2 CO2, 3 NADH, 1 FADH2, 1 GTP. Marking points: correct order of acids, the two CO2 exits, the three NADH steps, the one FADH2 step, the GTP step and regeneration of OAA.
Electron transport system on the inner mitochondrial membrane (NCERT Fig. 12.4)
Draw a horizontal band for the inner membrane with 'intermembrane space' above and 'matrix' below. Embed five blocks left to right: Complex I (NADH dehydrogenase), Complex II (succinate dehydrogenase), Complex III (cytochrome bc1), Complex IV (cytochrome c oxidase, cyt a, a3, Cu), Complex V (ATP synthase). Draw UQ as a small mobile circle inside the membrane between I/II and III, and cytochrome c as a small circle on the upper (outer) surface between III and IV. Arrows: NADH + H+ → NAD+ at complex I; FADH2 → FAD at complex II; electron arrows I → UQ, II → UQ, UQ → III → cyt c → IV; from IV, '½O2 + 2H+ → H2O' in the matrix. Draw H+ arrows pumped upward at complexes I, III and IV, and H+ flowing back down through F0 of complex V with 'ADP + Pi → ATP' at the F1 head in the matrix. Marking points: order of complexes, the two mobile carriers, oxygen as final acceptor, the proton gradient and ATP synthase.
ATP synthase: F<sub>0</sub> and F<sub>1</sub> particles
Draw a section of the inner membrane. Inside the membrane draw a cylinder labelled F0 (integral membrane protein complex, proton channel). On the matrix side draw a knob attached by a stalk labelled F1 (peripheral membrane protein complex, site of ATP synthesis). Show H+ entering F0 from the intermembrane space and leaving into the matrix, and write 'ADP + Pi → ATP' beside F1. Add the note '2H+ per ATP'. Marking points: F0 in membrane as the channel, F1 projecting into the matrix with the catalytic site, direction of proton flow (intermembrane space to matrix).
Interrelationship among metabolic pathways: the amphibolic pathway (NCERT Fig. 12.5)
Down the centre draw the main line: carbohydrates → glucose → (glycolysis) PGAL → pyruvic acid → acetyl CoA → citric acid cycle → CO2 + H2O with ATP. On the left draw fats → glycerol with an arrow joining at PGAL, and fats → fatty acids with an arrow joining at acetyl CoA. On the right draw proteins → amino acids with three arrows joining at pyruvic acid, at acetyl CoA and at the citric acid cycle (α-ketoglutaric acid, oxaloacetic acid). Make the arrows at acetyl CoA and the cycle double-headed and label them 'withdrawn for synthesis of fatty acids / amino acids'. Marking points: entry points of glycerol, fatty acids and amino acids; the double-headed arrows that show anabolism; the word amphibolic in the title.
Mitochondrion with the sites of respiration marked
Draw an oval with a smooth outer membrane and a folded inner membrane forming cristae; label outer membrane, inner membrane, intermembrane space, cristae and matrix. Write 'glycolysis' outside the mitochondrion in the cytoplasm with an arrow carrying pyruvic acid across both membranes into the matrix. In the matrix write 'link reaction (pyruvic acid → acetyl CoA)' and 'citric acid cycle'. Along a crista write 'ETS and oxidative phosphorylation (complexes I to V)'. Marking points: four labelled parts, and the three processes at their correct sites.
Respiratory balance sheet as a flow chart
Three boxes left to right: Glycolysis (cytoplasm), Link reaction + Citric acid cycle (matrix), ETS (inner membrane). Under box 1 write '2 ATP, 2 NADH'; under box 2 write '2 NADH (link) + 6 NADH + 2 FADH2 + 2 GTP (two turns)'; draw arrows carrying '10 NADH' and '2 FADH2' into box 3 and write '10 × 3 = 30 ATP, 2 × 2 = 4 ATP'. At the bottom write 'Total 2 + 2 + 30 + 4 = 38; less 2 ATP for transporting glycolytic NADH into the mitochondrion = 36 net (NCERT)'. Marking points: substrate-level ATP shown separately from ETS ATP, correct coenzyme counts, the 36/38 explanation.
TextbookNCERT questions the board keeps asking
12.1 Differentiate between (a) Respiration and Combustion (b) Glycolysis and Krebs' cycle (c) Aerobic respiration and Fermentation.5 m
(a) Respiration vs combustion. Respiration is a biochemical oxidation of glucose inside living cells, controlled by enzymes, occurring in many small steps at cell temperature; the energy is released gradually and a part of it is trapped as ATP, and there is no light. Combustion is a physico-chemical oxidation outside cells, needs no enzymes, occurs in a single uncontrolled step at high temperature, and releases all the energy at once as heat and light; none is stored.
(b) Glycolysis vs Krebs' cycle. Glycolysis occurs in the cytoplasm; the Krebs cycle in the mitochondrial matrix. Glycolysis is a linear pathway of ten steps; the Krebs cycle is cyclic. Glycolysis needs no oxygen and occurs in aerobes and anaerobes; the Krebs cycle occurs only under aerobic conditions. Glycolysis converts one glucose (6C) into two pyruvic acid (3C) with no CO2 released; the Krebs cycle oxidises acetyl CoA completely, releasing two CO2 per turn. Glycolysis uses 2 ATP and makes 4 (net 2) with 2 NADH; each turn of the Krebs cycle makes 1 GTP, 3 NADH and 1 FADH2.
(c) Aerobic respiration vs fermentation. Aerobic respiration needs oxygen; fermentation does not. Aerobic respiration degrades glucose completely to CO2 and H2O; fermentation breaks it down partially to ethanol and CO2 or lactic acid. Aerobic respiration occurs in cytoplasm and mitochondria; fermentation only in the cytoplasm. Aerobic respiration gives a net 36 ATP per glucose; fermentation only 2. In aerobic respiration NADH is oxidised vigorously by the ETS with O2 as acceptor; in fermentation NADH is oxidised slowly by pyruvate or acetaldehyde.
12.2 What are respiratory substrates? Name the most common respiratory substrate.2 m
Respiratory substrates are the organic compounds that are oxidised in living cells during respiration to release energy. They include carbohydrates, proteins, fats and organic acids. The most common respiratory substrate is glucose. In plants, sucrose is first split by invertase into glucose and fructose, which then enter glycolysis; fats and proteins are used only when carbohydrates are short.
12.3 Give the schematic representation of glycolysis.5 m
Draw the NCERT Fig. 12.1 flow chart (see diagrams). Glucose → (hexokinase, ATP → ADP) glucose-6-phosphate → fructose-6-phosphate → (phosphofructokinase, ATP → ADP) fructose 1,6-bisphosphate → (aldolase) dihydroxyacetone phosphate ⇌ 3-phosphoglyceraldehyde (2 molecules) → (NAD+ → NADH + H+) 1,3-bisphosphoglycerate → (ADP → ATP) 3-phosphoglycerate → 2-phosphoglycerate → (enolase, H2O removed) phosphoenolpyruvate → (pyruvate kinase, ADP → ATP) pyruvic acid. Site: cytoplasm. Net: 2 ATP, 2 NADH + H+, 2 pyruvic acid per glucose. State that ATP is used at two steps (glucose → glucose-6-phosphate; fructose-6-phosphate → fructose 1,6-bisphosphate) and formed at two steps (BPGA → 3-PGA; PEP → pyruvate).
12.4 What are the main steps in aerobic respiration? Where does it take place?3 m
Aerobic respiration takes place in the mitochondria (after glycolysis in the cytoplasm). Its main steps are: (i) Glycolysis in the cytoplasm, glucose → 2 pyruvic acid + 2 ATP + 2 NADH. (ii) Oxidative decarboxylation of pyruvate (link reaction) in the mitochondrial matrix, pyruvic acid + CoA + NAD+ → acetyl CoA + CO2 + NADH + H+, by pyruvic dehydrogenase. (iii) Citric acid (Krebs) cycle in the matrix, acetyl CoA oxidised to 2 CO2 with 3 NADH, 1 FADH2 and 1 GTP per turn. (iv) Electron transport system and oxidative phosphorylation on the inner mitochondrial membrane, where NADH and FADH2 are oxidised, electrons pass through complexes I to IV to oxygen (forming water) and ATP is made by ATP synthase (complex V) through chemiosmosis. Net yield 36 ATP per glucose.
12.5 Give the schematic representation of an overall view of Krebs' cycle.5 m
Draw NCERT Fig. 12.3 (see diagrams). Acetyl CoA (2C) + oxaloacetic acid (4C) + H2O → (citrate synthase, CoA released) citric acid (6C) → isocitric acid → (CO2 out, NAD+ → NADH + H+) α-ketoglutaric acid (5C) → (CO2 out, NAD+ → NADH + H+, CoA in) succinyl-CoA (4C) → (GDP + Pi → GTP, CoA out) succinic acid → (FAD → FADH2) fumaric acid → (+ H2O) malic acid → (NAD+ → NADH + H+) oxaloacetic acid. Site: mitochondrial matrix. Per turn: 2 CO2, 3 NADH + H+, 1 FADH2, 1 GTP (→ ATP). Overall for one pyruvic acid including the link reaction: Pyruvic acid + 4NAD+ + FAD + 2H2O + ADP + Pi → 3CO2 + 4NADH + 4H+ + FADH2 + ATP.
12.6 Explain ETS.5 m
The electron transport system is the chain of carriers on the inner mitochondrial membrane through which electrons from NADH and FADH2 are passed to oxygen, with the released energy used to make ATP. Complex I (NADH dehydrogenase) oxidises NADH from the matrix and passes the electrons to ubiquinone, a mobile carrier in the membrane. Complex II (succinate dehydrogenase) passes electrons from FADH2, formed at the succinate step of the citric acid cycle, also to ubiquinone. Reduced ubiquinone is oxidised by complex III (cytochrome bc1), which transfers the electrons to cytochrome c, a small protein on the outer surface of the inner membrane acting as a mobile carrier between complexes III and IV. Complex IV (cytochrome c oxidase, containing cytochromes a and a3 and two copper centres) passes the electrons to molecular oxygen, the final acceptor, which is reduced to water. As electrons flow, protons are pumped into the intermembrane space; they return to the matrix through the F0 channel of ATP synthase (complex V), and the F1 head makes ATP from ADP and Pi (2H+ per ATP). One NADH yields 3 ATP and one FADH2 2 ATP. Because ATP is made using energy from oxidation, the process is oxidative phosphorylation. Oxygen is needed only at the end but drives the whole system by removing hydrogen and regenerating NAD+ and FAD.
12.7 Distinguish between the following: (a) Aerobic respiration and Anaerobic respiration (b) Glycolysis and Fermentation (c) Glycolysis and Citric acid cycle.5 m
(a) Aerobic vs anaerobic respiration. Aerobic needs molecular O2; anaerobic does not. Aerobic gives complete oxidation to CO2 and H2O; anaerobic gives incomplete oxidation to ethanol + CO2 or lactic acid. Aerobic occurs in cytoplasm and mitochondria; anaerobic only in the cytoplasm. Aerobic yields 36 ATP net per glucose; anaerobic only 2. In aerobic respiration the final hydrogen acceptor is O2; in anaerobic it is an organic molecule (pyruvate or acetaldehyde).
(b) Glycolysis vs fermentation. Glycolysis is the breakdown of glucose to two pyruvic acid; fermentation is the further anaerobic conversion of pyruvic acid to ethanol + CO2 or lactic acid. Glycolysis produces NADH + H+ and a net 2 ATP; fermentation produces no ATP itself but reoxidises NADH to NAD+ so that glycolysis can continue. Glycolysis is common to aerobic and anaerobic organisms; fermentation occurs only under anaerobic conditions.
(c) Glycolysis vs citric acid cycle. Cytoplasm vs mitochondrial matrix. Linear vs cyclic pathway. No oxygen needed vs needs oxygen indirectly to regenerate NAD+ and FAD. Glucose (6C) → 2 pyruvate (3C), no CO2 released vs acetyl CoA → 2 CO2 per turn. Net 2 ATP + 2 NADH per glucose vs 1 GTP + 3 NADH + 1 FADH2 per turn (2 turns per glucose).
12.8 What are the assumptions made during the calculation of net gain of ATP?3 m
The net gain of 36 ATP per glucose is a theoretical figure calculated on four assumptions: (i) there is a sequential, orderly pathway functioning, with one substrate forming the next and with glycolysis, TCA cycle and ETS following one after another; (ii) the NADH synthesised in glycolysis is transferred into the mitochondria and undergoes oxidative phosphorylation; (iii) none of the intermediates in the pathway are utilised to synthesise any other compound; (iv) only glucose is being respired, and no other alternative substrates enter the pathway at any intermediary stage. These are not valid in a living system because all pathways work simultaneously and do not take place one after another, substrates enter the pathway and are withdrawn from it as needed, ATP is utilised as and when needed, and enzymatic rates are controlled by many means.
12.9 Discuss 'The respiratory pathway is an amphibolic pathway.'3 m
A catabolic pathway breaks molecules down; an anabolic pathway builds them. The respiratory pathway does both, so it is called amphibolic. Catabolic role: besides glucose, other substrates are broken down through it. Fats are split into glycerol and fatty acids; fatty acids are degraded to acetyl CoA, which enters the citric acid cycle, and glycerol enters glycolysis as PGAL. Proteins are degraded to amino acids, which enter as pyruvate, acetyl CoA or intermediates of the citric acid cycle after deamination. Anabolic role: the same intermediates are withdrawn for synthesis. When the cell needs fatty acids, acetyl CoA is withdrawn from the pathway; many amino acids are synthesised from intermediates of the citric acid cycle such as α-ketoglutaric acid and oxaloacetic acid; glycerol for fat synthesis comes from PGAL. Since the respiratory pathway is thus involved in both breakdown and synthesis, it is better called an amphibolic pathway than a purely catabolic one (NCERT Fig. 12.5).
12.10 Define RQ. What is its value for fats?2 m
The respiratory quotient (RQ) or respiratory ratio is the ratio of the volume of CO2 evolved to the volume of O2 consumed in respiration: RQ = volume of CO2 evolved / volume of O2 consumed. Its value depends on the substrate. For fats RQ is less than 1, about 0.7, because fats are poor in oxygen and need extra O2 for oxidation. For tripalmitin: 2(C51H98O6) + 145O2 → 102CO2 + 98H2O; RQ = 102/145 = 0.7. (For carbohydrates RQ = 1; for proteins about 0.9.)
12.11 What is oxidative phosphorylation?3 m
Oxidative phosphorylation is the synthesis of ATP from ADP and inorganic phosphate using the energy released when the reduced coenzymes NADH and FADH2 are oxidised through the electron transport system with oxygen as the final electron acceptor. As electrons pass through complexes I, III and IV on the inner mitochondrial membrane, protons are pumped into the intermembrane space, creating a proton gradient. Protons flow back into the matrix through the F0 channel of ATP synthase (complex V), and this flow drives the F1 headpiece to make ATP; 2H+ pass through F0 per ATP. One NADH gives 3 ATP and one FADH2 gives 2 ATP. It differs from substrate-level phosphorylation, where ATP is made by direct transfer of phosphate from a substrate, and from photophosphorylation, where the energy comes from light.
12.12 What is the significance of step-wise release of energy in respiration?3 m
The complete oxidation of glucose releases a large amount of energy (about 686 kcal per mole is often quoted). If it were all released in one step, as in combustion, it would be lost as heat and light and could damage the cell. In respiration the oxidation occurs in a series of small, enzyme-controlled steps, and this has three advantages. (i) A greater fraction of the energy can be trapped in the high-energy bonds of ATP instead of being lost as heat, so the efficiency is higher. (ii) The rate of the pathway can be regulated at each enzyme step according to the cell's needs, so ATP is made as and when required. (iii) The intermediates formed at each step (PGAL, pyruvate, acetyl CoA, α-ketoglutarate, oxaloacetate) can be withdrawn for the synthesis of other biomolecules such as fatty acids and amino acids, which is what makes the pathway amphibolic.
Exemplar (SA) Oxygen is critical for aerobic respiration. Explain its role with respect to ETS.3 m
Oxygen does not take part directly in glycolysis or in the citric acid cycle; its role is limited to the terminal stage of the ETS. Yet its presence is vital because it is the final hydrogen (electron) acceptor: complex IV (cytochrome c oxidase) transfers the electrons carried down the chain to molecular O2, which combines with protons to form water. By accepting the electrons, oxygen keeps the whole chain flowing, which keeps the proton gradient and ATP synthesis going, and regenerates NAD+ and FAD from NADH and FADH2. Without oxygen the carriers stay reduced, NAD+ and FAD are not regenerated, the citric acid cycle and the link reaction stop, and the cell is left with only glycolysis and fermentation. NCERT sums it up: oxygen drives the whole process by removing hydrogen from the system.
Exemplar (SA) Why is the anaerobic respiration or fermentation much less efficient than aerobic respiration in terms of energy yield?3 m
In fermentation glucose is only partially oxidised: the products, ethanol or lactic acid, still hold most of the energy of glucose. The NADH + H+ formed in glycolysis is not oxidised through the ETS but is used to reduce pyruvate or acetaldehyde, so no ATP is made from it. There is no citric acid cycle, no ETS and no oxidative phosphorylation, which is where most of the ATP of aerobic respiration comes from. The only ATP is the net 2 ATP of glycolysis, and less than 7 per cent of the energy in glucose is released, not all of it trapped in ATP. In aerobic respiration glucose is completely oxidised to CO2 and H2O and the reduced coenzymes are oxidised by oxygen through the ETS, giving a net 36 ATP per glucose.
Previous years and frequently askedBoard questions with model answers
MCQ Which biomolecule is common to the respiration-mediated breakdown of fats, carbohydrates and proteins?- Pyruvic acid
- Acetyl CoA
- Fructose 1,6-bisphosphate
- Glucose-6-phosphate
Frequently asked1 m
MCQ Which of the following statements about the Krebs cycle is incorrect?- There are three points in the cycle where NAD+ is reduced to NADH + H+
- The cycle starts with condensation of the acetyl group with pyruvic acid
- GTP is synthesised during the conversion of succinyl-CoA to succinic acid
- There is one point where FAD is reduced to FADH2
Frequently asked1 m
MCQ The energy-releasing metabolic process in which a substrate is oxidised without an external electron acceptor is called- Aerobic respiration
- Glycolysis
- Fermentation
- Photorespiration
Frequently asked1 m
MCQ The chemiosmotic coupling hypothesis of oxidative phosphorylation proposes that ATP is formed because- ADP is pumped out of the matrix into the intermembrane space
- High-energy bonds are formed in mitochondrial proteins
- A proton gradient forms across the inner mitochondrial membrane
- The inner membrane becomes permeable to ADP
Frequently asked1 m
MCQ The electron transport system in a eukaryotic cell is located in the- Outer mitochondrial membrane
- Intermembrane space
- Inner mitochondrial membrane
- Mitochondrial matrix
Frequently asked1 m
MCQ During which stage of aerobic respiration is the greatest number of ATP molecules formed from ADP?- Glycolysis
- Conversion of pyruvic acid to acetyl CoA
- Krebs cycle
- Electron transport chain
Frequently asked1 m
MCQ In alcoholic fermentation- Triose phosphate is the electron donor while acetaldehyde is the electron acceptor
- Triose phosphate is the electron donor while pyruvic acid is the electron acceptor
- Oxygen is the electron acceptor
- There is no electron donor
Frequently asked1 m
MCQ Pyruvic acid, the key product of glycolysis, can have many metabolic fates. Under aerobic conditions it forms- Lactic acid
- Ethanol + CO2
- Acetyl CoA + CO2
- CO2 + H2O directly
Frequently asked1 m
MCQ The respiratory quotient of tripalmitin is about- 1.0
- 0.9
- 0.7
- 1.3
Frequently asked1 m
Assertion–Reason Assertion (A): Fermentation releases much less energy than aerobic respiration. Reason (R): In fermentation glucose is only partially oxidised and the NADH of glycolysis is used to reduce pyruvate or acetaldehyde instead of being oxidised through the ETS.- Both A and R are true and R is the correct explanation of A
- Both A and R are true but R is not the correct explanation of A
- A is true but R is false
- A is false but R is true
Frequently asked1 m
Assertion–Reason Assertion (A): Glycolysis occurs in the cytoplasm of all living organisms. Reason (R): Glycolysis requires molecular oxygen for the oxidation of glyceraldehyde-3-phosphate.- Both A and R are true and R is the correct explanation of A
- Both A and R are true but R is not the correct explanation of A
- A is true but R is false
- A is false but R is true
Frequently asked1 m
Assertion–Reason Assertion (A): Oxygen is essential for aerobic respiration even though it does not take part directly in the citric acid cycle. Reason (R): Oxygen is the final hydrogen (electron) acceptor at the end of the ETS, and by removing hydrogen it regenerates NAD+ and FAD needed by the cycle.- Both A and R are true and R is the correct explanation of A
- Both A and R are true but R is not the correct explanation of A
- A is true but R is false
- A is false but R is true
Frequently asked1 m
Assertion–Reason Assertion (A): ATP synthase is called complex V of the electron transport system. Reason (R): ATP synthase transfers electrons from cytochrome c to molecular oxygen.- Both A and R are true and R is the correct explanation of A
- Both A and R are true but R is not the correct explanation of A
- A is true but R is false
- A is false but R is true
Frequently asked1 m
Very short answer Define respiratory quotient. Why is the RQ of fats less than one?Frequently asked2 m
RQ is the ratio of the volume of CO2 evolved to the volume of O2 consumed in respiration: RQ = volume CO2 evolved / volume O2 consumed. (1 mark)
Fats contain much less oxygen in proportion to carbon and hydrogen than carbohydrates do, so more O2 has to be taken in to oxidise them fully, and less CO2 is released per O2 consumed. For tripalmitin, 145 O2 are consumed and 102 CO2 released, RQ = 0.7. (1 mark)
Very short answer What is substrate-level phosphorylation? Give one example each from glycolysis and the citric acid cycle.Frequently asked2 m
Substrate-level phosphorylation is the formation of ATP (or GTP) by the direct transfer of a phosphate group from a phosphorylated substrate to ADP (or GDP), without an electron transport chain or proton gradient. (1 mark)
Glycolysis: conversion of 1,3-bisphosphoglycerate to 3-phosphoglycerate, or of phosphoenolpyruvate to pyruvic acid, each forming ATP. Citric acid cycle: conversion of succinyl-CoA to succinic acid, forming GTP, which then gives ATP. (1 mark)
Very short answer Name the two parts of ATP synthase and state the function of each.Frequently asked2 m
F1: the headpiece, a peripheral membrane protein complex projecting into the matrix, which contains the site for synthesis of ATP from ADP and inorganic phosphate. (1 mark)
F0: an integral membrane protein complex that forms the channel through which protons cross the inner membrane from the intermembrane space to the matrix; the passage of 2H+ through it is coupled to the synthesis of one ATP at F1. (1 mark)
Very short answer Plants do not have specialised organs for gas exchange. Give two reasons why they can manage without them.Frequently asked2 m
(i) Each plant part takes care of its own gas-exchange needs through stomata and lenticels, and plants do not present a great demand for gas exchange since roots, stems and leaves respire at rates far lower than animals. (ii) Living cells lie close to the surface of the plant, and the bulk of the body is dead cells or loosely packed parenchyma with large intercellular spaces, so gases diffuse easily; in addition, photosynthesising cells release O2 within the cell. (1 mark each for any two)
Very short answer What is oxidative decarboxylation? Name the enzyme and the coenzymes involved when pyruvate undergoes it.Frequently asked2 m
Oxidative decarboxylation is a reaction in which a molecule loses CO2 and is simultaneously oxidised, the hydrogen being taken up by a coenzyme. Pyruvic acid (3C) is converted in the mitochondrial matrix to acetyl CoA (2C) + CO2 + NADH + H+. (1 mark)
Enzyme: pyruvic dehydrogenase (needs Mg2+). Coenzymes: NAD+ and coenzyme A. (1 mark)
Short answer Describe alcoholic fermentation in yeast. Why can naturally fermented drinks not exceed about 13 per cent alcohol?Frequently asked3 m
Under anaerobic conditions yeast converts the pyruvic acid formed in glycolysis into ethanol and CO2 in two steps. First, pyruvic acid is decarboxylated to acetaldehyde by pyruvic acid decarboxylase, releasing CO2. Then acetaldehyde is reduced to ethanol by alcohol dehydrogenase, with NADH + H+ being oxidised to NAD+; this regeneration of NAD+ allows glycolysis to continue. Overall: C6H12O6 → 2C2H5OH + 2CO2, with a net gain of only 2 ATP from glycolysis; less than 7 per cent of the energy of glucose is released. (2 marks)
Ethanol is toxic to the yeast itself. As fermentation proceeds the alcohol accumulates, and yeasts poison themselves to death when the concentration reaches about 13 per cent, so fermentation stops; stronger drinks are made by distillation. (1 mark)
Short answer State the assumptions on which the net gain of ATP in aerobic respiration is calculated, and say why they do not hold in a living cell.Frequently asked3 m
Assumptions: (i) a sequential, orderly pathway with one substrate forming the next and glycolysis, TCA cycle and ETS following one after another; (ii) the NADH made in glycolysis is transferred into the mitochondria and undergoes oxidative phosphorylation; (iii) none of the intermediates is used to synthesise any other compound; (iv) only glucose is respired, with no other substrate entering at an intermediate stage. (2 marks)
In a living cell all pathways work simultaneously rather than one after another, substrates enter and leave the pathway at many points (the pathway is amphibolic), ATP is used as and when needed, and enzyme rates are regulated, so the actual yield varies; the figure of 36 ATP is theoretical. (1 mark)
Short answer Explain the chemiosmotic mechanism of ATP synthesis in mitochondria.Frequently asked3 m
As electrons from NADH and FADH2 pass through complexes I, III and IV of the ETS on the inner mitochondrial membrane, the energy released is used to pump protons from the matrix into the intermembrane space. This creates a proton (electrochemical) gradient across the inner membrane, which is impermeable to protons except through ATP synthase. (1 mark)
ATP synthase (complex V) has F0, an integral membrane protein complex forming a proton channel, and F1, a peripheral headpiece in the matrix containing the catalytic site. Protons flow back into the matrix through F0 down the gradient, and this flow is coupled to the synthesis of ATP from ADP and Pi at F1; for each ATP, 2H+ pass through F0. (1 mark)
Since the energy comes from the oxidation of coenzymes with oxygen as the final acceptor, the process is called oxidative phosphorylation; one NADH yields 3 ATP and one FADH2 yields 2 ATP. (1 mark)
Short answer Give three differences between glycolysis and the citric acid cycle.Frequently asked3 m
(i) Site: glycolysis occurs in the cytoplasm; the citric acid cycle in the mitochondrial matrix. (ii) Oxygen: glycolysis needs no oxygen and occurs in all organisms; the citric acid cycle runs only under aerobic conditions because NAD+ and FAD are regenerated by the ETS. (iii) Pathway and products: glycolysis is linear, converting one glucose (6C) into two pyruvic acid (3C) with a net 2 ATP and 2 NADH and no CO2; the citric acid cycle is cyclic, oxidising acetyl CoA to two CO2 per turn with 3 NADH, 1 FADH2 and 1 GTP, and regenerating oxaloacetic acid. (1 mark each)
Short answer Write the three possible fates of pyruvic acid formed in glycolysis, naming the enzyme and the condition for each.Frequently asked3 m
(i) Lactic acid fermentation: under anaerobic conditions in some bacteria and in animal muscle short of oxygen, pyruvic acid is reduced by NADH + H+ to lactic acid by lactate dehydrogenase; no CO2 is released. (ii) Alcoholic fermentation: under anaerobic conditions in yeast, pyruvic acid is decarboxylated to acetaldehyde by pyruvic acid decarboxylase and acetaldehyde is reduced to ethanol by alcohol dehydrogenase, releasing CO2. (iii) Aerobic respiration: in the presence of oxygen pyruvic acid enters the mitochondrial matrix and undergoes oxidative decarboxylation by pyruvic dehydrogenase (with NAD+ and CoA) to acetyl CoA, CO2 and NADH + H+; acetyl CoA then enters the citric acid cycle. (1 mark each)
Long answer Describe glycolysis with a schematic representation. Indicate the steps at which ATP is used and formed and state the net gain per glucose.Frequently asked5 m
Glycolysis (EMP pathway, after Embden, Meyerhof and Parnas) is the partial oxidation of glucose to two molecules of pyruvic acid in the cytoplasm; it needs no oxygen and occurs in all living organisms. (1 mark)
Scheme (draw NCERT Fig. 12.1): Glucose → (hexokinase, ATP used) glucose-6-phosphate → fructose-6-phosphate → (phosphofructokinase, ATP used) fructose 1,6-bisphosphate → (aldolase) dihydroxyacetone phosphate + 3-phosphoglyceraldehyde (DHAP isomerises to PGAL, so two PGAL per glucose) → (NAD+ → NADH + H+) 1,3-bisphosphoglycerate → (ATP formed) 3-phosphoglycerate → 2-phosphoglycerate → (enolase, H2O removed) phosphoenolpyruvate → (pyruvate kinase, ATP formed) pyruvic acid. (2 marks)
ATP used: at the conversion of glucose to glucose-6-phosphate and of fructose-6-phosphate to fructose 1,6-bisphosphate (2 ATP). ATP formed: at the conversion of BPGA to 3-PGA and of PEP to pyruvic acid, by substrate-level phosphorylation; each occurs twice per glucose (4 ATP). NADH: formed when PGAL is oxidised to BPGA, twice per glucose. (1 mark)
Net gain per glucose: 2 ATP (4 formed minus 2 used), 2 NADH + H+ and 2 pyruvic acid. Pyruvic acid then goes to lactic acid fermentation, alcoholic fermentation or aerobic respiration depending on the organism and on oxygen. (1 mark)
Long answer Describe the citric acid cycle with a labelled schematic. Give its overall equation for one molecule of pyruvic acid and the tally of products per turn.Frequently asked5 m
The tricarboxylic acid (citric acid or Krebs) cycle was elucidated by Hans Krebs in 1937 and occurs in the mitochondrial matrix. Pyruvic acid first undergoes oxidative decarboxylation by pyruvic dehydrogenase to acetyl CoA + CO2 + NADH + H+. (1 mark)
Cycle (draw NCERT Fig. 12.3): Acetyl CoA (2C) condenses with oxaloacetic acid (4C) and water to give citric acid (6C), catalysed by citrate synthase; CoA is released. Citrate is isomerised to isocitrate. Isocitrate loses CO2 and is oxidised (NAD+ → NADH + H+) to α-ketoglutaric acid (5C). α-Ketoglutaric acid loses a second CO2, is oxidised (second NADH + H+) and combines with CoA to form succinyl-CoA (4C). Succinyl-CoA is converted to succinic acid with the synthesis of GTP from GDP + Pi (substrate-level phosphorylation); GTP then forms ATP from ADP. Succinic acid is oxidised by succinate dehydrogenase to fumaric acid, with FAD reduced to FADH2. Fumaric acid adds water to form malic acid, which is oxidised (third NADH + H+) to oxaloacetic acid, regenerating the acceptor. (2 marks)
Per turn: 2 CO2, 3 NADH + H+, 1 FADH2, 1 GTP (= 1 ATP); two turns per glucose. (1 mark)
Overall equation for one pyruvic acid (with the link reaction): Pyruvic acid + 4NAD+ + FAD + 2H2O + ADP + Pi → 3CO2 + 4NADH + 4H+ + FADH2 + ATP. The continued oxidation of acetyl CoA requires continued replenishment of oxaloacetic acid and regeneration of NAD+ and FAD by the ETS. (1 mark)
Long answer With a labelled diagram, describe the electron transport system of mitochondria and explain how ATP is synthesised. What is the role of oxygen?Frequently asked5 m
The ETS is located on the inner mitochondrial membrane (draw NCERT Fig. 12.4 with the membrane, intermembrane space above, matrix below, and complexes I to V). (1 mark for the diagram)
Carriers: NADH from the matrix is oxidised by complex I (NADH dehydrogenase), which passes the electrons to ubiquinone, a mobile carrier within the membrane. Ubiquinone also receives electrons from FADH2 through complex II (succinate dehydrogenase). Reduced ubiquinone is oxidised by complex III (cytochrome bc1 complex), which transfers the electrons to cytochrome c, a small protein on the outer surface of the inner membrane that shuttles between complexes III and IV. Complex IV (cytochrome c oxidase), containing cytochromes a and a3 and two copper centres, transfers the electrons to molecular oxygen, which is reduced to water. (2 marks)
ATP synthesis: as electrons pass through the complexes, protons are pumped into the intermembrane space, creating a proton gradient. Protons return to the matrix through the F0 channel of ATP synthase (complex V), and the F1 headpiece uses this flow to make ATP from ADP and Pi; 2H+ pass per ATP. One NADH gives 3 ATP, one FADH2 gives 2 ATP, because FADH2 enters after complex I. This is oxidative phosphorylation. (1 mark)
Role of oxygen: oxygen acts only at the terminal step, as the final hydrogen (electron) acceptor, but its presence is vital because it drives the whole process by removing hydrogen from the system, regenerating NAD+ and FAD and keeping the citric acid cycle and the proton pumping going. (1 mark)
Long answer Prepare the respiratory balance sheet for the complete aerobic oxidation of one molecule of glucose, showing the ATP obtained at each stage. Why does NCERT give the net gain as 36 ATP?Frequently asked5 m
Assume 3 ATP per NADH and 2 ATP per FADH2 oxidised in the ETS, and the four NCERT assumptions (sequential pathway, glycolytic NADH enters the mitochondrion, no intermediate withdrawn, only glucose respired). (1 mark)
- Glycolysis (cytoplasm): 2 ATP by substrate-level phosphorylation (4 formed, 2 used) + 2 NADH + H+.
- Oxidative decarboxylation of 2 pyruvate (matrix): 2 NADH + H+.
- Citric acid cycle, 2 turns (matrix): 2 GTP = 2 ATP + 6 NADH + H+ + 2 FADH2.
- ETS (inner membrane): 10 NADH × 3 = 30 ATP; 2 FADH2 × 2 = 4 ATP.
(2 marks for the stage-wise tally)
Total: 2 + 2 + 30 + 4 = 38 ATP. (1 mark)
The 2 NADH of glycolysis are made in the cytoplasm and must be transported across the mitochondrial membranes to reach the ETS; this transport costs the equivalent of 2 ATP, so the net gain is 38 − 2 = 36 ATP per glucose, the figure NCERT gives. In fermentation, by contrast, the net gain is only 2 ATP. (1 mark)
Case-based A student sets up three respirometers with germinating seeds. Flask A holds germinating wheat grains, flask B holds germinating castor seeds, and flask C holds germinating wheat grains but is sealed so that no oxygen can enter. After some hours the student measures the CO2 released and the O2 consumed. Flask A shows the two volumes almost equal; flask B shows less CO2 released than O2 consumed; flask C shows CO2 released although no O2 was consumed.
(i) Define the quantity the student is measuring.
(ii) State the approximate RQ in flasks A and B and name the substrate being respired in each.
(iii) Explain the observation in flask C and name the process going on in the seeds.
(iv) Why would a value near 0.9 be expected from seeds respiring mainly proteins?Frequently asked4 m
(i) The respiratory quotient, the ratio of the volume of CO2 evolved to the volume of O2 consumed in respiration. (1 mark)
(ii) Flask A: RQ about 1, the wheat grains are respiring carbohydrate (starch → glucose), C6H12O6 + 6O2 → 6CO2 + 6H2O. Flask B: RQ below 1, about 0.7, the castor seeds are respiring fat (oil), which is poor in oxygen and needs more O2 per CO2 released, as for tripalmitin, 102/145 = 0.7. (1 mark)
(iii) Without oxygen the seeds carry out fermentation (anaerobic respiration): glycolysis gives pyruvic acid, which is converted to ethanol and CO2 by pyruvic acid decarboxylase and alcohol dehydrogenase, so CO2 is released although no O2 is consumed; the RQ cannot be defined meaningfully (it tends to infinity). (1 mark)
(iv) Proteins contain more oxygen relative to carbon than fats but less than carbohydrates, so their RQ lies between the two; NCERT gives about 0.9 for proteins as the respiratory substrate. (1 mark)
Case-based In a bakery, yeast is mixed into dough and left in a warm place. The dough rises and smells faintly of alcohol. The same baker makes wine from grape juice with the same yeast, but finds that the alcohol content never rises beyond about 13 per cent no matter how long the juice is kept, and that the yeast in the wine is dead by the end.
(i) Name the process occurring in the dough and write its overall equation.
(ii) Name the two enzymes involved and the coenzyme that is recycled.
(iii) Why does the alcohol content stop at about 13 per cent?
(iv) How much of the energy of glucose is released in this process, and how many ATP does the yeast gain per glucose?Frequently asked4 m
(i) Alcoholic fermentation, an anaerobic process in yeast: C6H12O6 → 2C2H5OH + 2CO2 + energy; the CO2 makes the dough rise. (1 mark)
(ii) Pyruvic acid decarboxylase converts pyruvic acid to acetaldehyde and CO2; alcohol dehydrogenase reduces acetaldehyde to ethanol. The coenzyme NADH + H+ formed in glycolysis is oxidised back to NAD+, which is recycled so that glycolysis can continue. (1 mark)
(iii) Ethanol is toxic to yeast. Yeasts poison themselves to death when the alcohol concentration reaches about 13 per cent, so fermentation stops at that level; stronger spirits are obtained only by distillation. (1 mark)
(iv) Less than 7 per cent of the energy in glucose is released in fermentation, and not all of it is trapped in ATP; the net gain is only the 2 ATP of glycolysis per glucose, compared with 36 in aerobic respiration. (1 mark)
Test yourselfPractice quiz
Marks lost every yearCommon mistakes
- Writing NADPH for the coenzyme reduced in glycolysis or the citric acid cycle. Respiration uses NAD+/NADH and FAD/FADH2; NADPH belongs to photosynthesis. Examiners cut the mark for the wrong coenzyme even when the step is right.
- Saying that pyruvic acid enters the Krebs cycle. Pyruvic acid is first converted to acetyl CoA in the matrix, and it is acetyl CoA that condenses with oxaloacetic acid. NEET 2017 built a whole question on this.
- Placing FADH2 at the wrong step or GTP at the wrong step. FADH2 is made only at succinate → fumarate; GTP only at succinyl-CoA → succinate. Students who draw the cycle from memory often swap these.
- Giving 38 ATP as the NCERT answer. NCERT gives a net gain of 36 ATP, with the 2 ATP difference being the cost of moving glycolytic NADH into the mitochondrion. Write 36 and be able to show 38 minus 2.
- Confusing the sites. Glycolysis is in the cytoplasm, not the mitochondrion; the citric acid cycle is in the matrix, not the inner membrane; the ETS is on the inner membrane, not in the matrix. A 1-mark site question is lost by a single wrong word.
- Calling oxygen a participant in the Krebs cycle. Oxygen is used only at the end of the ETS as the final hydrogen acceptor; the cycle needs it indirectly, to regenerate NAD+ and FAD. Say this exactly.
- Defining RQ as amount or moles instead of volume, or inverting it. RQ is the volume of CO2 evolved divided by the volume of O2 consumed; tripalmitin gives 102/145 = 0.7, not 145/102.
- Writing fermentation as 'respiration without oxygen' and stopping there. The examiner wants the enzymes (pyruvic acid decarboxylase, alcohol dehydrogenase, lactate dehydrogenase), the reoxidation of NADH to NAD+, the 2 ATP and the less-than-7-per-cent figure.
- Mixing up F0 and F1. F1 is the headpiece in the matrix with the ATP-synthesising site; F0 is the membrane-embedded proton channel. And ATP synthase carries protons, not electrons.
- Answering the amphibolic question with a definition only. The mark is for one catabolic example and one anabolic example with named molecules: fatty acids to acetyl CoA, and acetyl CoA withdrawn for fatty-acid synthesis.
How to prepareStrategy for this chapter
This chapter is one pathway told in order, so prepare it in order and do not skip the counts. Spend the first sitting on glycolysis: draw Fig. 12.1 three times from memory until you can mark the two ATP-using steps, the NADH step and the two ATP-forming steps without looking, and write the net gain at the bottom each time. Spend the second sitting on the fates of pyruvate (Fig. 12.2) and the citric acid cycle (Fig. 12.3); for the cycle learn the order of the acids as a chant (citrate, isocitrate, α-ketoglutarate, succinyl-CoA, succinate, fumarate, malate, oxaloacetate) and pin the three events to their steps: GTP at succinyl-CoA, FADH2 at succinate, NADH at isocitrate, α-ketoglutarate and malate.
The third sitting is the ETS (Fig. 12.4): five complexes in order, ubiquinone and cytochrome c as the two mobile carriers, oxygen at the end, F0 and F1 with 2H+ per ATP, 3 ATP per NADH and 2 per FADH2. Then do the balance sheet once on paper and reach 38 and then 36; the four assumptions are a guaranteed 2 or 3 marks, so memorise them as four short lines.
The last sitting is the small sections that give cheap marks: why plants need no breathing organs (five reasons), the amphibolic pathway with two examples each way, and RQ with the tripalmitin arithmetic. Finish by writing the NCERT exercise 12.1 and 12.7 comparison tables; they are the most likely 5-mark question in a school paper. In the exam, give every biochemical answer as a labelled scheme plus a tally line; the tally (ATP, NADH, FADH2, CO2) is where the marks sit.